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LevelPE — Mechanical
SubjectPE — Mechanical
Year2025 BS
Exam sessionModel questions
Full marks80
Time allowed480 minutes
Questions10, all with step-by-step solutions
A

Mechanical Engineering

Select the best answer.

10 questions·1 mark each
1Multiple choice1 mark

AC system: Qs=15kWQ_s = 15\,\text{kW}, Ts=14CT_s = 14^\circ\text{C}, Tr=24CT_r = 24^\circ\text{C}, cp=1.005kJ/(kg\cdotK)c_p = 1.005\,\text{kJ/(kg\cdot K)}:

m˙=Qscp(TrTs)\dot{m} = \frac{Q_s}{c_p(T_r - T_s)}
  • a

    0.75kg/s0.75\,\text{kg/s}

  • b

    1.49kg/s1.49\,\text{kg/s}

  • c

    2.24kg/s2.24\,\text{kg/s}

  • d

    3.00kg/s3.00\,\text{kg/s}

Correct answer: b

1.49kg/s1.49\,\text{kg/s}

m˙=151.005×10=1.49kg/s\dot{m} = \frac{15}{1.005 \times 10} = 1.49\,\text{kg/s}
hvac
2Multiple choice1 mark

Counterflow HX: Th,in=150T_{h,in}=150^\circ, Th,out=90T_{h,out}=90^\circ, Tc,in=30T_{c,in}=30^\circ, Tc,out=80T_{c,out}=80^\circ. LMTD:

ΔTlm=ΔT1ΔT2ln(ΔT1/ΔT2)\Delta T_{lm} = \frac{\Delta T_1 - \Delta T_2}{\ln(\Delta T_1/\Delta T_2)}
  • a

    48.1C48.1^\circ\text{C}

  • b

    55.5C55.5^\circ\text{C}

  • c

    64.9C64.9^\circ\text{C}

  • d

    70.0C70.0^\circ\text{C}

Correct answer: c

64.9C64.9^\circ\text{C}

ΔT1=70, ΔT2=60\Delta T_1 = 70^\circ,\ \Delta T_2 = 60^\circ ΔTlm=10ln(70/60)=100.1542=64.9C\Delta T_{lm} = \frac{10}{\ln(70/60)} = \frac{10}{0.1542} = 64.9^\circ\text{C}
thermal-systems
3Multiple choice1 mark

Shaft: M=500N\cdotmM = 500\,\text{N\cdot m}, T=400N\cdotmT = 400\,\text{N\cdot m}. Equivalent torque (max shear stress theory):

Te=M2+T2T_e = \sqrt{M^2 + T^2}
  • a

    500N\cdotm500\,\text{N\cdot m}

  • b

    640N\cdotm640\,\text{N\cdot m}

  • c

    750N\cdotm750\,\text{N\cdot m}

  • d

    900N\cdotm900\,\text{N\cdot m}

Correct answer: b

640N\cdotm640\,\text{N\cdot m}

Te=250,000+160,000=410,000=640N\cdotmT_e = \sqrt{250{,}000 + 160{,}000} = \sqrt{410{,}000} = 640\,\text{N\cdot m}
machine-design
4Multiple choice1 mark

Spring-mass system: m=5kgm = 5\,\text{kg}, k=2,000N/mk = 2{,}000\,\text{N/m}. Natural frequency:

fn=12πk/mf_n = \frac{1}{2\pi}\sqrt{k/m}
  • a

    2.01Hz2.01\,\text{Hz}

  • b

    3.18Hz3.18\,\text{Hz}

  • c

    4.50Hz4.50\,\text{Hz}

  • d

    6.37Hz6.37\,\text{Hz}

Correct answer: b

3.18Hz3.18\,\text{Hz}

fn=12π400=206.283=3.18Hzf_n = \frac{1}{2\pi}\sqrt{400} = \frac{20}{6.283} = 3.18\,\text{Hz}
vibration
5Multiple choice1 mark

Centrifugal pump: Q=0.05m3/sQ = 0.05\,\text{m}^3/\text{s}, H=30mH = 30\,\text{m}, γ=9,810N/m3\gamma = 9{,}810\,\text{N/m}^3:

Pw=γQHP_w = \gamma Q H
  • a

    7.36kW7.36\,\text{kW}

  • b

    14.72kW14.72\,\text{kW}

  • c

    22.07kW22.07\,\text{kW}

  • d

    29.43kW29.43\,\text{kW}

Correct answer: b

14.72kW14.72\,\text{kW}

Pw=9810×0.05×30=14,715W=14.72kWP_w = 9810 \times 0.05 \times 30 = 14{,}715\,\text{W} = 14.72\,\text{kW}
fluid-systems
6Multiple choice1 mark

Thin-walled cylinder: r=0.5mr = 0.5\,\text{m}, t=10mmt = 10\,\text{mm}, p=2MPap = 2\,\text{MPa}. Hoop stress:

σh=prt\sigma_h = \frac{pr}{t}
  • a

    50MPa50\,\text{MPa}

  • b

    100MPa100\,\text{MPa}

  • c

    150MPa150\,\text{MPa}

  • d

    200MPa200\,\text{MPa}

Correct answer: b

100MPa100\,\text{MPa}

σh=2×50010=100MPa\sigma_h = \frac{2 \times 500}{10} = 100\,\text{MPa}

Hoop stress is twice the longitudinal stress.

pressure-vessels
7Multiple choice1 mark

Cooling tower: m˙w=50kg/s\dot{m}_w = 50\,\text{kg/s}, ΔT=10C\Delta T = 10^\circ\text{C}, cp=4.18kJ/(kg\cdotK)c_p = 4.18\,\text{kJ/(kg\cdot K)}:

Q˙=m˙wcpΔT\dot{Q} = \dot{m}_w c_p \Delta T
  • a

    1,045kW1{,}045\,\text{kW}

  • b

    2,090kW2{,}090\,\text{kW}

  • c

    3,135kW3{,}135\,\text{kW}

  • d

    4,180kW4{,}180\,\text{kW}

Correct answer: b

2,090kW2{,}090\,\text{kW}

Q˙=50×4.18×10=2,090kW\dot{Q} = 50 \times 4.18 \times 10 = 2{,}090\,\text{kW}
hvac
8Multiple choice1 mark

Rankine cycle: turbine work wt=1,200kJ/kgw_t = 1{,}200\,\text{kJ/kg}, pump work wp=10kJ/kgw_p = 10\,\text{kJ/kg}. Net work:

  • a

    1,190kJ/kg1{,}190\,\text{kJ/kg}

  • b

    1,200kJ/kg1{,}200\,\text{kJ/kg}

  • c

    1,210kJ/kg1{,}210\,\text{kJ/kg}

  • d

    1,100kJ/kg1{,}100\,\text{kJ/kg}

Correct answer: a

1,190kJ/kg1{,}190\,\text{kJ/kg}

wnet=wtwp=120010=1,190kJ/kgw_{net} = w_t - w_p = 1200 - 10 = 1{,}190\,\text{kJ/kg}
thermal-systems
9Multiple choice1 mark

Bolt: Sp=600MPaS_p = 600\,\text{MPa}, At=150mm2A_t = 150\,\text{mm}^2. Preload at 75% proof:

Fi=0.75SpAtF_i = 0.75 \cdot S_p \cdot A_t
  • a

    45.0kN45.0\,\text{kN}

  • b

    67.5kN67.5\,\text{kN}

  • c

    90.0kN90.0\,\text{kN}

  • d

    112.5kN112.5\,\text{kN}

Correct answer: b

67.5kN67.5\,\text{kN}

Fi=0.75×600×150=67,500N=67.5kNF_i = 0.75 \times 600 \times 150 = 67{,}500\,\text{N} = 67.5\,\text{kN}
machine-design
10Multiple choice1 mark

Shaft critical speed Ncr=3,000rpmN_{cr} = 3{,}000\,\text{rpm}. Safe range above critical starts at 1.3Ncr1.3 N_{cr}:

  • a

    3,000rpm3{,}000\,\text{rpm}

  • b

    3,600rpm3{,}600\,\text{rpm}

  • c

    3,900rpm3{,}900\,\text{rpm}

  • d

    4,500rpm4{,}500\,\text{rpm}

Correct answer: c

3,900rpm3{,}900\,\text{rpm}

1.3×3,000=3,900rpm1.3 \times 3{,}000 = 3{,}900\,\text{rpm}

Avoid operating between 2,1002{,}100 and 3,900rpm3{,}900\,\text{rpm}.

vibration

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Yes. Every question on this PE — Mechanical past paper includes a step-by-step solution, plus instant AI feedback when you attempt it on Kekkei.
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The PE — Mechanical PE — Mechanical 2025 paper carries 80 full marks and is meant to be completed in 480 minutes, across 10 questions.
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