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LevelNEB Class 12
StreamScience
SubjectChemistry (Technical Stream)
Year2082 BS
Exam sessionRegular (annual)
Full marks75
Time allowed180 minutes
Questions36, all with step-by-step solutions
A

Group 'A'

Rewrite the correct option of each question in your answer sheet.

11 questions·1 mark each
1Multiple choice1 mark

Which of the following indicator is suitable for the titration between ethanoic acid and NaOH?

  • a

    Methyl orange

  • b

    Phenolphthalein

  • c

    Methyl red

  • d

    Litmus paper

Correct answer: b

Phenolphthalein

Ethanoic acid is a weak acid and NaOH is a strong base, so the equivalence point is on the basic side (pH > 7). Phenolphthalein (range 8.3-10) is the suitable indicator.

acid-base-titrationindicators
2Multiple choice1 mark

The enthalpy change for the reaction;

N2(g)+3H2(g)2NH3(g)N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

is 93.7KJmol1-93.7\,\text{KJmol}^{-1}, what kind of reaction is it?

  • a

    exothermic

  • b

    endothermic

  • c

    isothermal

  • d

    isobaric

Correct answer: a

exothermic

A negative enthalpy change (ΔH<0\Delta H < 0) means heat is released, so the reaction is exothermic.

thermochemistryenthalpy
3Multiple choice1 mark

Which of the following species can act both as Bronsted acid and Bronsted base?

  • a

    HCl

  • b

    H2PO4H_2PO_4

  • c

    HCO3HCO_3^-

  • d

    O2O_2

Correct answer: c

HCO3HCO_3^-

HCO3HCO_3^- can donate a proton (acting as an acid to give CO32CO_3^{2-}) and accept a proton (acting as a base to give H2CO3H_2CO_3), so it is amphiprotic.

bronsted-acid-baseamphoteric
4Multiple choice1 mark

When copper is heated in air at above 11000C1100\,^0C, which of the following compounds is formed?

  • a

    CuO

  • b

    Cu(OH)2Cu(OH)_2

  • c

    CuCO3CuCO_3

  • d

    Cu2OCu_2O

Correct answer: d

Cu2OCu_2O

Below ~1000°C copper forms black CuO, but above ~1100°C CuO decomposes to red cuprous oxide Cu2OCu_2O. So Cu2OCu_2O is formed.

copperoxides
5Multiple choice1 mark

For which manufacturing process, Bessemer converter is used?

  • a

    Pig iron

  • b

    Steel

  • c

    Wrought iron

  • d

    Cast iron

Correct answer: b

Steel

The Bessemer converter blows air through molten pig iron to remove impurities and produce steel.

metallurgybessemer-process
6Multiple choice1 mark

The substance 'A' which reacts with gangue to form fusible mass. The substance 'A' is called

  • a

    Flux

  • b

    Catalyst

  • c

    Ore

  • d

    Slag

Correct answer: a

Flux

A flux combines with the infusible gangue to form an easily fusible slag.

metallurgyflux
7Multiple choice1 mark

An organic compound (A) boiled with water gives phenol. Predict the compound (A).

  • a

    Chlorobenzene

  • b

    Benzenediazonium chloride

  • c

    Aniline

  • d

    Benzenesulphonic acid

Correct answer: b

Benzenediazonium chloride

Benzenediazonium chloride (C6H5N2+ClC_6H_5N_2^+Cl^-) on boiling with water gives phenol: C6H5N2Cl+H2OC6H5OH+N2+HClC_6H_5N_2Cl + H_2O \rightarrow C_6H_5OH + N_2 + HCl. Chlorobenzene needs harsh conditions (Dow process), so the standard 'boiled with water' answer is benzenediazonium chloride.

aromatic-compoundsphenol
8Multiple choice1 mark

Which of the following compounds cannot reduce Fehling's solution?

  • a

    Benzaldehyde

  • b

    Formaldehyde

  • c

    Acetaldehyde

  • d

    Butyraldehyde

Correct answer: a

Benzaldehyde

Fehling's solution is reduced by aliphatic aldehydes. Aromatic aldehydes like benzaldehyde do not reduce Fehling's solution.

aldehydesfehling-test
9Multiple choice1 mark

Which of the following methods can you apply to convert rectified spirit into absolute alcohol?

  • a

    Steam distillation

  • b

    Vacuum distillation

  • c

    Simple distillation

  • d

    Azeotropic distillation

Correct answer: d

Azeotropic distillation

Rectified spirit (95.6% ethanol) is an azeotrope, so ordinary distillation cannot give absolute alcohol; azeotropic distillation (with benzene) is used.

alcoholsdistillation
10Multiple choice1 mark
(A)(ii) Zn/H2O(i) O3ethanal+methanal(A) \xrightarrow[\text{(ii) } Zn/H_2O]{\text{(i) } O_3} \text{ethanal} + \text{methanal}

Identify the compound (A)?

  • a

    Ethene

  • b

    Propene

  • c

    But-1-ene

  • d

    But-2-ene

Correct answer: b

Propene

Ozonolysis cleaves the C=C double bond into two carbonyl fragments. Ethanal (CH3CHOCH_3CHO) + methanal (HCHOHCHO) recombine across the broken double bond to give CH3CH=CH2CH_3-CH=CH_2, i.e. propene.

ozonolysisalkenes
11Multiple choice1 mark

Which of the following drugs is used to reduce body temperature during high fever?

  • a

    Analgesic

  • b

    Antiseptic

  • c

    Antipyritic

  • d

    Disinfectant

Correct answer: c

Antipyritic

An antipyretic is a drug used to reduce fever (body temperature).

medicinal-chemistryantipyretic
B

Group 'B'

Short answer questions

17 questions·5 marks each
12aShort answer1 mark

The fundamental principle of titration is based on the law of chemical equivalence.

a) What does it mean?

The law of chemical equivalence states that whenever two substances react chemically, they always do so in the ratio of their chemical equivalents. In other words, one gram-equivalent of a substance reacts exactly with one gram-equivalent of another substance.

Applied to titration, this means at the end point the number of gram-equivalents (or milliequivalents) of the acid is exactly equal to the number of gram-equivalents of the base:

equivalents of acid=equivalents of base\text{equivalents of acid} = \text{equivalents of base}
titrationlaw-of-equivalence
12bShort answer2 marks

b) Derive normality equation using the law of equivalence.

By definition, the number of gram-equivalents of a solute is related to its normality (N)(N) and volume (V)(V):

Number of gram-equivalents=N×V(litre)=N×V(mL)1000\text{Number of gram-equivalents} = N \times V\,(\text{litre}) = \frac{N \times V\,(\text{mL})}{1000}

Let an acid (normality N1N_1, volume V1V_1) be titrated against a base (normality N2N_2, volume V2V_2). By the law of equivalence, at the end point:

equivalents of acid=equivalents of base\text{equivalents of acid} = \text{equivalents of base} N1V11000=N2V21000\frac{N_1 V_1}{1000} = \frac{N_2 V_2}{1000}

Cancelling the common factor gives the normality equation:

N1V1=N2V2\boxed{N_1 V_1 = N_2 V_2}
titrationnormality
12cNumeric answer2 marks

c) 10cc of N/2 HCl, 30cc of N/10 HNO3HNO_3 and 60cc of N/5 H2SO4H_2SO_4 are mixed. Calculate the normality of the mixture.

Or

State and explain first law of thermodynamics. Give the name of any two home appliances that work on the principle of 1st1^{st} law of thermodynamics. [3+2][3+2]

Numeric answer (N)

normalitytitration
13aShort answer1 mark

Acidic strength of solution can be measured in term of pH value.

a) Define pH of a solution.

The pH of a solution is defined as the negative logarithm (base 10) of the hydrogen ion (or hydronium ion) concentration expressed in mol L1^{-1}:

pH=log10[H+]pH = -\log_{10}[H^+]

It is a measure of the acidity or basicity of a solution; lower pH means more acidic.

phacids
13bShort answer1 mark

b) What is the application of pH in our daily life?

pH has many practical uses in daily life:

  • Agriculture: testing soil pH to decide which crops to grow and whether to add lime/fertilizer.
  • Medicine/health: monitoring the pH of blood and body fluids (blood pH must stay near 7.4); treating acidity of the stomach with antacids.
  • Food and beverages: controlling acidity in foods, soft drinks and preservation.
  • Personal care products: ensuring shampoos, soaps and cosmetics have a skin-friendly pH.
  • Water and waste-water treatment: adjusting pH for safe drinking water.
phapplications
13cShort answer2 marks

c) What is pOH and how is it related to pH?

pOH is the negative logarithm (base 10) of the hydroxide ion concentration (in mol L1^{-1}):

pOH=log10[OH]pOH = -\log_{10}[OH^-]

Relation with pH: In water, the ionic product is [H+][OH]=Kw=1014[H^+][OH^-] = K_w = 10^{-14} at 25 °C. Taking negative logarithm of both sides:

log[H+]log[OH]=logKw-\log[H^+] - \log[OH^-] = -\log K_w pH+pOH=14(at 25C)\boxed{pH + pOH = 14 \quad (\text{at } 25\,^\circ C)}
pohph
13dNumeric answer1 mark

d) Calculate the pH of 5×1045\times10^{-4} M H2SO4H_2SO_4 solution.

Numeric answer

phcalculation
14Short answer5 marks

Derive and explain integrated rate equation and half life for a zero order reaction.

Zero Order Reaction

A reaction is zero order when its rate is independent of the concentration of the reactant.

Consider: AProductsA \rightarrow \text{Products}

Integrated Rate Equation

For a zero order reaction the rate equals the rate constant kk:

d[A]dt=k[A]0=k-\frac{d[A]}{dt} = k[A]^0 = k

Separating variables and integrating between limits ([A]0[A]_0 at t=0t=0 and [A][A] at time tt):

[A]0[A]d[A]=k0tdt\int_{[A]_0}^{[A]} d[A] = -k\int_0^t dt [A][A]0=kt[A] - [A]_0 = -kt [A]=[A]0kt\boxed{[A] = [A]_0 - kt}

Explanation: This is a straight-line equation. A plot of [A][A] versus tt gives a straight line with slope =k= -k and intercept =[A]0= [A]_0. The concentration falls linearly with time. Also k=[A]0[A]tk = \dfrac{[A]_0 - [A]}{t}, whose units are mol L1^{-1} s1^{-1}.

Half Life (t1/2t_{1/2})

Half life is the time taken for the concentration to fall to half its initial value, i.e. [A]=[A]02[A] = \dfrac{[A]_0}{2}. Substituting in the integrated equation:

[A]02=[A]0kt1/2\frac{[A]_0}{2} = [A]_0 - k\,t_{1/2} kt1/2=[A]02k\,t_{1/2} = \frac{[A]_0}{2} t1/2=[A]02k\boxed{t_{1/2} = \frac{[A]_0}{2k}}

Conclusion: For a zero order reaction, the half life is directly proportional to the initial concentration [A]0[A]_0.

chemical-kineticszero-order-reaction
15aShort answer1 mark

Standard hydrogen electrode can be used as reference electrode.

a) Define standard hydrogen electrode.

A standard hydrogen electrode (SHE) is a reference electrode consisting of a platinised platinum plate dipped in a 1 M solution of H+^+ ions (1 M HCl), through which pure hydrogen gas at 1 atm pressure is bubbled, all maintained at 25 °C (298 K). Its electrode potential is arbitrarily taken to be zero (E=0.00E^\circ = 0.00 V).

Electrode reaction: 2H++2eH22H^+ + 2e^- \rightleftharpoons H_2

electrochemistryhydrogen-electrode
15bShort answer1 mark

b) What is the major application of standard hydrogen electrode?

The major application of the standard hydrogen electrode is that it is used as a reference (standard) electrode to measure the standard electrode (reduction) potentials of other electrodes/half-cells, since its own potential is fixed at zero.

electrochemistryhydrogen-electrode
15cShort answer2 marks

c) Draw well labeled diagram of standard hydrogen electrode.

Standard Hydrogen Electrode (description of the labelled diagram):

The diagram should show:

  • A glass jacket/tube with a side inlet for H2_2 gas at 1 atm pressure.
  • A platinum wire carrying a platinised platinum (Pt black) plate at its lower end.
  • The Pt plate dipped in 1 M HCl (1 M H+^+) solution.
  • Hydrogen gas bubbling over the Pt plate and escaping through holes at the bottom of the glass tube.
  • A salt bridge / connecting tube to complete the circuit with the other half-cell.
        H2 gas in (1 atm)
              |
        ______v______
       |  glass tube |
       |   | wire |  |
       |   |      |  |---> to external circuit
       |  [Pt black plate]
       |  o o o (H2 bubbles)
       |_____________|
     1 M HCl (1 M H+) solution

(Label: H2_2 gas inlet at 1 atm, platinised Pt plate, 1 M H+^+ / HCl solution, hydrogen bubbles, connection to circuit.)

electrochemistrydiagram
15dShort answer1 mark

d) What is meant by standard electrode potential?

The standard electrode potential (EE^\circ) of an electrode is the potential developed at the electrode when it is in contact with its ions at unit concentration (1 M), with any gases at 1 atm pressure and the temperature at 25 °C (298 K), measured relative to the standard hydrogen electrode (whose potential is taken as zero).

electrochemistryelectrode-potential
16Short answer5 marks

Derive the equation ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S. Why useful work of system is called free energy? [4+1][4+1]

Derivation of ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S

Gibbs free energy is defined as:

G=HTSG = H - TS

where HH = enthalpy, SS = entropy, TT = absolute temperature.

Consider a process in which the state changes from initial state 1 to final state 2 at constant temperature TT:

G1=H1TS1G2=H2TS2G_1 = H_1 - TS_1 \qquad G_2 = H_2 - TS_2

Subtracting:

G2G1=(H2H1)T(S2S1)G_2 - G_1 = (H_2 - H_1) - T(S_2 - S_1) ΔG=ΔHTΔS\boxed{\Delta G = \Delta H - T\Delta S}

This is the Gibbs–Helmholtz relation, used to predict the spontaneity of a process (ΔG<0\Delta G < 0 → spontaneous).

Why useful work is called free energy

For a process carried out at constant temperature and pressure, it can be shown that the decrease in Gibbs energy equals the maximum useful (non-expansion / net) work obtainable from the system:

ΔG=Wuseful, max-\Delta G = W_{\text{useful, max}}

Thus the quantity GG represents the portion of the system's energy that is "free" or available to be converted into useful work. The remaining energy (TΔST\Delta S) is bound/unavailable. Hence the useful work of the system is called free energy.

thermodynamicsgibbs-free-energy
17aShort answer2 marks

Differentiate between:

a) Calcination and roasting

CalcinationRoasting
Ore is heated strongly in the absence or limited supply of air.Ore is heated strongly in the presence of excess air.
Applied mainly to carbonate and hydrated (oxide) ores.Applied mainly to sulphide ores.
Removes moisture, CO2_2 and volatile impurities and converts ore to oxide.Converts sulphide ore to oxide and removes volatile impurities (S as SO2_2).
Example: CaCO3ΔCaO+CO2CaCO_3 \xrightarrow{\Delta} CaO + CO_2Example: 2ZnS+3O2Δ2ZnO+2SO22ZnS + 3O_2 \xrightarrow{\Delta} 2ZnO + 2SO_2
metallurgycalcination-roasting
17bShort answer3 marks

b) Froth floatation and magnetic separation process.

Froth Floatation Process

  • Used chiefly for the concentration of sulphide ores (e.g. galena, zinc blende, copper pyrites).
  • It works on the difference in wettability of ore and gangue. The powdered ore is mixed with water, a frothing agent (pine oil) and a collector in a tank, and air is blown through.
  • The ore particles become wetted by oil and rise up with the froth (which is skimmed off), while the gangue is wetted by water and settles at the bottom.

Magnetic Separation Process

  • Used when either the ore or the gangue is magnetic while the other is non-magnetic.
  • The powdered ore is dropped on a belt moving over two rollers, one of which is an electromagnet.
  • The magnetic component is attracted and falls near the magnetic roller, while the non-magnetic component is thrown farther away, forming two separate heaps.
  • Example: separating magnetic tin ore (cassiterite/wolframite) or iron ore from non-magnetic impurities.
metallurgyore-concentration
18Short answer5 marks

Write down the functional isomer of C3H6OC_3H_6O with their IUPAC names. How are they distinguished by Tollen's reagent? How would you obtain these isomers by dehydrogenation of alcohols? [2+1+2][2+1+2]

Functional Isomers of C3H6OC_3H_6O

The two functional isomers are:

  1. PropanalCH3CH2CHOCH_3CH_2CHO (an aldehyde)
  2. Propanone (acetone)CH3COCH3CH_3COCH_3 (a ketone)

They have the same molecular formula but different functional groups, hence are functional isomers.

Distinction by Tollen's Reagent

Tollen's reagent is ammoniacal silver nitrate, [Ag(NH3)2]+[Ag(NH_3)_2]^+.

  • Propanal (aldehyde) reduces Tollen's reagent and gives a shining silver mirror:
CH3CH2CHO+2[Ag(NH3)2]++3OHCH3CH2COO+2Ag+4NH3+2H2OCH_3CH_2CHO + 2[Ag(NH_3)_2]^+ + 3OH^- \rightarrow CH_3CH_2COO^- + 2Ag\downarrow + 4NH_3 + 2H_2O
  • Propanone (ketone) does not reduce Tollen's reagent — no silver mirror is formed.

Thus the aldehyde gives a silver mirror while the ketone does not.

Preparation by Dehydrogenation of Alcohols

Passing alcohol vapour over heated copper at 300 °C removes hydrogen (dehydrogenation):

  • Primary alcohol → aldehyde:
CH3CH2CH2OH300CCuCH3CH2CHO+H2(propanal)CH_3CH_2CH_2OH \xrightarrow[300\,^\circ C]{Cu} CH_3CH_2CHO + H_2 \quad (\text{propanal})
  • Secondary alcohol → ketone:
CH3CH(OH)CH3300CCuCH3COCH3+H2(propanone)CH_3CH(OH)CH_3 \xrightarrow[300\,^\circ C]{Cu} CH_3COCH_3 + H_2 \quad (\text{propanone})
functional-isomerscarbonyl-compounds
19Short answer5 marks

Write an example of each of the following reactions: [1+1+1+1+1][1+1+1+1+1]

a) Dow's process

b) Wurtz reaction

c) 2, 4- DNP test

d) Preparation of alcohol from ester.

e) Preparation of phenol from benzene sulphonic acid

Or

The vapour of organic compound (A), if inhaled causes the loss of consciousness and if heated with conc.HNO3HNO_3 forms a component of tear gas.

i) How would you prepare compound (A) by using one of the isomers of C2H6OC_2H_6O. [2][2]

ii) What happens when compound (A) is: [1+1+1][1+1+1]

a) exposed in air

b) heated with Ag powder

c) heated with aqueous alkali

a) Dow's process (chlorobenzene → phenol):

C6H5Cl+NaOH300atm623KC6H5ONaH+C6H5OH+NaClC_6H_5Cl + NaOH \xrightarrow[300\,atm]{623\,K} C_6H_5ONa \xrightarrow{H^+} C_6H_5OH + NaCl

b) Wurtz reaction (alkyl halide + Na in dry ether → alkane):

2CH3Cl+2Nadry etherCH3CH3+2NaCl2CH_3Cl + 2Na \xrightarrow{\text{dry ether}} CH_3-CH_3 + 2NaCl

c) 2,4-DNP test (aldehydes/ketones give orange-yellow 2,4-dinitrophenylhydrazone):

CH3CHO+H2NNHC6H3(NO2)2CH3CH=NNHC6H3(NO2)2+H2OCH_3CHO + H_2N-NH-C_6H_3(NO_2)_2 \rightarrow CH_3CH=N-NH-C_6H_3(NO_2)_2 + H_2O

d) Preparation of alcohol from ester (reduction with LiAlH4_4, or hydrolysis):

CH3COOC2H5+4[H]LiAlH4CH3CH2OH+C2H5OHCH_3COOC_2H_5 + 4[H] \xrightarrow{LiAlH_4} CH_3CH_2OH + C_2H_5OH

e) Phenol from benzene sulphonic acid (alkali fusion):

C6H5SO3H+NaOHC6H5SO3NafusionNaOH,ΔC6H5ONaH+C6H5OHC_6H_5SO_3H + NaOH \rightarrow C_6H_5SO_3Na \xrightarrow[\text{fusion}]{NaOH,\,\Delta} C_6H_5ONa \xrightarrow{H^+} C_6H_5OH

Or (alternative)

Compound (A) is chloroform, CHCl3CHCl_3 (its vapour is an anaesthetic causing loss of consciousness; with conc. HNO3_3 it forms chloropicrin CCl3NO2CCl_3NO_2, a tear gas component).

i) Preparation of (A) from an isomer of C2H6OC_2H_6O: Ethanol (C2H5OHC_2H_5OH, an isomer of C2H6OC_2H_6O) is warmed with bleaching powder (or Cl2_2 + alkali) — the haloform reaction:

C2H5OHCl2CH3CHOCl2CCl3CHOCa(OH)2CHCl3+HCOOC_2H_5OH \xrightarrow{Cl_2} CH_3CHO \xrightarrow{Cl_2} CCl_3CHO \xrightarrow{Ca(OH)_2} CHCl_3 + HCOO^-

Overall: 2C2H5OH+6Cl2+Ca(OH)22CHCl3+(HCOO)2Ca+2C_2H_5OH + 6Cl_2 + Ca(OH)_2 \rightarrow 2CHCl_3 + (HCOO)_2Ca + \ldots

ii) Reactions of chloroform:

(a) Exposed in air (light): slowly oxidised to the poisonous gas phosgene:

2CHCl3+O2light2COCl2+2HCl2CHCl_3 + O_2 \xrightarrow{\text{light}} 2COCl_2 + 2HCl

(b) Heated with Ag powder: gives acetylene:

2CHCl3+6AgΔC2H2+6AgCl2CHCl_3 + 6Ag \xrightarrow{\Delta} C_2H_2 + 6AgCl

(c) Heated with aqueous (dilute) alkali: gives formate (sodium/potassium formate):

CHCl3+4NaOHHCOONa+3NaCl+2H2OCHCl_3 + 4NaOH \rightarrow HCOONa + 3NaCl + 2H_2O
named-reactionsorganic-chemistry
C

Group 'C'

Long answer questions

8 questions·8 marks each
20Long answer8 marks

Define the rate of chemical reaction. How do concentration, temperature, catalyst and surface area of reactants affect the rate of reaction? The half life period of first order reaction is 3 hours. Calculate the time required to complete 87.5% of the reaction. [1+4+3][1+4+3]

Or

Differentiate between solubility and solubility product. How is solubility product principle helpful in the qualitative salt analysis? [2+6][2+6]

Rate of reaction = change in concentration of reactant or product per unit time. Factors: increasing concentration increases rate (more collisions); increasing temperature increases rate (more molecules cross activation energy); a catalyst increases rate by lowering activation energy; greater surface area of reactant increases rate. Numerical: 87.5% completion means 3 half lives (50% → 75% → 87.5%). t=3×t1/2=3×3=9t = 3 \times t_{1/2} = 3 \times 3 = 9 hours.

chemical-kineticsrate-of-reaction
21aLong answer1 mark

Iron is a heavy metal and extracted from its oxide ore.

a) Write the name of any two ores of iron.

Haematite (Fe2O3Fe_2O_3) and magnetite (Fe3O4Fe_3O_4). (Also limonite, siderite.)

metallurgyiron-ores
21bLong answer3 marks

b) Draw the clean and labelled diagram of the blast furnace showing different zones.

Labelled diagram of the Blast Furnace (description):

The blast furnace is a tall (~30 m) steel chimney lined with fire-bricks. From top to bottom, the following must be shown and labelled:

  • Charging cup-and-cone hopper (top): for feeding the charge (roasted ore + coke + limestone).
  • Flue/waste gas outlet (top): hot gases (mainly CO, CO2_2, N2_2) leave here.
  • Zone of reduction (upper, ~400–700 °C): where Fe2_2O3_3 is reduced by CO.
  • Zone of slag formation / fusion (middle, ~800–1000 °C): CaCO3_3 decomposes; CaO + SiO2_2 form slag.
  • Zone of combustion / fusion (lower, ~1500–1900 °C): coke burns in the hot air blast.
  • Tuyeres (bottom sides): pipes that blow in a hot air blast.
  • Tap holes (bottom): an upper one for molten slag and a lower one for molten iron (pig iron).
          Charge (ore+coke+limestone) + waste gas out
        ===========  cup & cone hopper  ===========
        |   Zone of Reduction   (~400-700°C)       |
        |   Zone of Slag Formation (~800-1000°C)   |
        |   Zone of Fusion/Combustion (~1500°C+)   |
   air->|--[tuyeres]                  [tuyeres]--<-air
        |   slag tap -->  molten iron tap -->      |
        ============================================

(Label each zone with its temperature, the tuyeres, the hot air blast, the slag and molten iron tap holes, and the flue-gas outlet.)

metallurgyblast-furnacediagram
21cLong answer2 marks

c) Write the reactions involved in different zones.

Reactions in the different zones of the blast furnace:

1. Zone of Combustion / Fusion (bottom, ~1500 °C): coke burns in the hot air blast and CO2_2 is reduced to CO:

C+O2CO2+heatC + O_2 \rightarrow CO_2 + \text{heat} CO2+C2COCO_2 + C \rightarrow 2CO

2. Zone of Reduction (upper, ~400–700 °C): the iron oxide ore is reduced by CO to spongy iron:

Fe2O3+3CO2Fe+3CO2Fe_2O_3 + 3CO \rightarrow 2Fe + 3CO_2

(stepwise: 3Fe2O3+CO2Fe3O4+CO23Fe_2O_3 + CO \rightarrow 2Fe_3O_4 + CO_2; Fe3O4+CO3FeO+CO2Fe_3O_4 + CO \rightarrow 3FeO + CO_2; FeO+COFe+CO2FeO + CO \rightarrow Fe + CO_2).

3. Zone of Slag Formation / Fusion (~800–1000 °C): limestone decomposes and CaO removes the silica gangue as fusible slag:

CaCO3CaO+CO2CaCO_3 \rightarrow CaO + CO_2 CaO+SiO2CaSiO3(slag)CaO + SiO_2 \rightarrow CaSiO_3 \,(\text{slag})
metallurgyblast-furnace
21dLong answer2 marks

d) Mention the application of iron in our daily life.

Or

Explain the principle and process sketching a well labelled diagram for the extraction of zinc from its ore. What happen when zinc is exposed to moist air? [6+2][6+2]

Iron is used in construction (rods, beams, bridges), making machinery and tools, automobiles, railways, utensils, and as a raw material for steel and various alloys.

(Or-alternative: extraction of zinc from zinc blende — roasting ZnS to ZnO, then reduction with coke in a retort; 2ZnS+3O22ZnO+2SO22ZnS + 3O_2 \rightarrow 2ZnO + 2SO_2, ZnO+CZn+COZnO + C \rightarrow Zn + CO. When zinc is exposed to moist air it forms a protective layer of basic zinc carbonate ZnCO3Zn(OH)2ZnCO_3·Zn(OH)_2.)

metallurgyapplications-of-iron
22a-iLong answer2 marks

a) Radioactivity was discovered accidentally by a scientist Henry Becquerel (1896).

i) What is radioactivity? Write its unit.

Radioactivity is the spontaneous disintegration of an unstable atomic nucleus with the emission of alpha, beta or gamma radiation. Its SI unit is the becquerel (Bq); the older unit is the curie (Ci).

radioactivitynuclear-chemistry
22a-iiLong answer2 marks

ii) What is meant by artificial radioactivity? Write an example of it.

Artificial (induced) radioactivity is the radioactivity produced in a normally stable element by bombarding it with high-energy particles. Example: bombarding aluminium with alpha particles gives radioactive phosphorus-30: 1327Al+24He1530P+01n^{27}_{13}Al + ^{4}_{2}He \rightarrow ^{30}_{15}P + ^{1}_{0}n.

radioactivityartificial-radioactivity
22bLong answer4 marks

b) Mention one example and use of each of the following: [4][4]

i) Insecticide

ii) Synthetic polymer

iii) Antiseptic

iv) Fungicide

i) Insecticide: DDT — used to kill insects/mosquitoes. ii) Synthetic polymer: polythene (polyethene) — used for making bags, bottles, packaging. iii) Antiseptic: dettol (or tincture of iodine) — applied on wounds to kill/prevent microbes. iv) Fungicide: Bordeaux mixture (copper sulphate + lime) — used to kill fungi on crops.

applied-chemistrychemicals-in-daily-life

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