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LevelNEB Class 11
StreamScience
SubjectBiology
Year2078 BS
Exam sessionModel questions
Full marks75
Time allowed180 minutes
Questions22, all with step-by-step solutions
A

Group 'A'

Circle the correct one from given alternatives.

11 questions·1 mark each
1Multiple choice1 mark

Identify the correct bonding between nitrogen bases in DNA molecule from given pair.

  • a

    A = C

  • b

    A = G

  • c

    A = U

  • d

    A = T

Correct answer: d

A = T

In DNA, adenine pairs with thymine (A=T) via two hydrogen bonds. Answer: (d) A = T.

molecular-biologydnabase-pairing
2Multiple choice1 mark

Miller and Urey designed an experiment to recreate the environment of primitive earth to support the theory of biochemical origin of life. Which composition did he use to produce simple amino acids?

  • a

    Ammonia, Hydrogen, Nitrogen, and water vapour

  • b

    Ammonia, Methane, Hydrogen, and water vapour

  • c

    Ammonia, Oxygen, Carbon dioxide, and water vapour

  • d

    Ammonia, Nitrogen, Oxygen, and water vapour

Correct answer: b

Ammonia, Methane, Hydrogen, and water vapour

The Miller–Urey experiment used a mixture of ammonia, methane, hydrogen and water vapour. Answer: (b).

origin-of-lifemiller-urey
3Multiple choice1 mark

Which habitat is needed for xerophytic plants to survive?

  • a

    habitat with dry condition

  • b

    warm habitat

  • c

    habitat like desert

  • d

    habitat with little water

Correct answer: a

habitat with dry condition

Xerophytes are adapted to dry conditions (scarcity of water). The best answer is a habitat with dry condition. Answer: (a).

ecologyxerophytes
4Multiple choice1 mark

"Red rust is one of the destructive diseases in tea plants which results adverse effect on tea yield. It is caused by a type of algae." Which discipline of Biology is related to explain the above statement?

  • a

    Mycology

  • b

    Agronomy

  • c

    Pathology

  • d

    Phycology

Correct answer: d

Phycology

Since red rust of tea is caused by an alga (Cephaleuros), the relevant discipline is phycology (the study of algae). Answer: (d) Phycology.

branches-of-biologyphycology
5Multiple choice1 mark

Which of the following is a practice of in-situ conservation of biodiversity?

  • a

    Botanical garden

  • b

    Wildlife sanctuary

  • c

    Zoo

  • d

    Seed bank

Correct answer: b

Wildlife sanctuary

In-situ conservation protects species in their natural habitat — e.g. a wildlife sanctuary. (Botanical garden, zoo and seed bank are ex-situ.) Answer: (b) Wildlife sanctuary.

biodiversityconservation
6Multiple choice1 mark

Which one statement of the following tells the favor of prop root?

  • a

    It has the function of support

  • b

    It has the function of absorption

  • c

    It has the function of fixation

  • d

    It has the function of conduction

Correct answer: a

It has the function of support

Prop roots (e.g. in banyan) grow down from branches to the ground and give mechanical support to the heavy plant. Answer: (a) It has the function of support.

plant-morphologymodified-roots
7Multiple choice1 mark

Forelimbs (wings) of Dragon fly, Pteranodon, Hawk and Bat are given. What type of organs are these?

Wings of dragonfly, Pteranodon, hawk and bat

  • a

    Homologous

  • b

    Atavism

  • c

    Analogous

  • d

    Vestigial

Correct answer: c

Analogous

These wings perform the same function (flight) but have different structural origins/designs, so they are analogous organs (showing convergent evolution). Answer: (c) Analogous.

evolutionhomologous-analogous-organs
8Multiple choice1 mark

Which is the nearest ancestor of modern man?

  • a

    Homo sapiens neanderthalensis

  • b

    Homo sapiens sapiens

  • c

    Homo erectus erectus

  • d

    Homo erectus pekinensis

Correct answer: a

Homo sapiens neanderthalensis

The nearest (most recent) ancestor among the options is Homo sapiens neanderthalensis. Answer: (a).

evolutionhuman-evolution
9Multiple choice1 mark

In the given figure, X denotes an organ of the frog which produces a particular sound. What does that sound indicate?

Male frog with inflated vocal sac labelled X

  • a

    Danger

  • b

    Hunger

  • c

    Excitement

  • d

    Sex appeal

Correct answer: d

Sex appeal

X is the vocal sac of a male frog. The croaking sound produced is the mating call used to attract females, indicating sex appeal. Answer: (d) Sex appeal.

frogvocal-sacbehaviour
10Multiple choice1 mark

Trichocysts is an important organelle in Paramecium. Which activities does it associate for?

  • a

    Defense, offence, and adhesion

  • b

    Defense, reproduction, and nutrition

  • c

    Offence, osmoregulation, and defense

  • d

    Adhesion, osmoregulation, and reproduction

Correct answer: a

Defense, offence, and adhesion

Trichocysts are used by Paramecium for defence, offence (capturing prey) and anchorage/adhesion. Answer: (a) Defense, offence, and adhesion.

protozoaparameciumtrichocysts
11Multiple choice1 mark

IUCN noticed the one-horned rhino restricted in Chitwan national park of Nepal as a high-risk group. Its population has declined due to habitat loss, excessive poaching, low rate of breeding, human encroachment and other factors. According to this description, in which risk group does the one-horned rhino of Nepal fall?

  • a

    Near endangered

  • b

    Critically endangered

  • c

    Endangered

  • d

    Least endangered

Correct answer: c

Endangered

Given the high risk and population decline described, the one-horned rhino is classified as Endangered. Answer: (c) Endangered. (IUCN lists the greater one-horned rhino as Vulnerable globally, but per the description of high risk the intended answer here is Endangered/critically endangered.)

conservationiucn-categories
B

Group 'B'

Give short answer to the following questions.

8 questions·5 marks each
1Short answer5 marks

Write any five characteristics of Chlorophyceae.

Characteristics of Chlorophyceae (green algae): (1) they contain chlorophyll a and b, giving a grass-green colour; (2) the cell wall is made of an inner cellulose and outer pectose layer; (3) the reserve food is starch (stored in pyrenoids); (4) they are mostly aquatic (fresh water), some terrestrial; (5) the body is unicellular to filamentous/colonial (e.g. Chlamydomonas, Spirogyra, Volvox, Ulothrix); (6) motile cells/gametes bear two equal whiplash flagella; reproduction is vegetative, asexual (zoospores) and sexual.

algaechlorophyceae
2Short answer5 marks

'Gymnosperm is an advanced group than Pteridophyta'. Justify this statement with any five points.

OR

Compare between simple fruit and multiple fruit in two points. How can fruit play an important role for continuity of generation in plant life? (2×2+1)(2\times2+1)

Gymnosperm advanced over Pteridophyta (any five): (1) Gymnosperms are seed-bearing (seed habit) whereas pteridophytes reproduce by spores; (2) gymnosperms show heterospory leading to seed formation; (3) pollination by wind — no water needed for fertilisation, unlike pteridophytes which need water for swimming sperms; (4) development of pollen tube (siphonogamy); (5) well-developed vascular tissue and secondary growth; (6) reduced, dependent gametophyte; (7) ovule and naked seed present.

OR — Simple vs multiple fruit (two points): A simple fruit develops from a single ovary of a single flower (e.g. mango); a multiple fruit develops from the whole inflorescence (many flowers fusing together, e.g. jackfruit, pineapple). Fruit aids continuity of generation by protecting the developing seeds and aiding their dispersal (by wind, water, animals), ensuring the species spreads and reproduces.

gymnospermpteridophytafruit
3Short answer5 marks

How can ecological factors influence in pond ecosystem? Discuss it with suitable examples with respect to its structural and functional aspects. (2+1+2)(2+1+2)

A pond is a self-sufficient freshwater ecosystem. Structural aspects: abiotic factors (light, temperature, dissolved O₂/CO₂, pH, nutrients, water) and biotic components — producers (phytoplankton, algae, aquatic plants), consumers (zooplankton, insects, fish — primary/secondary/tertiary) and decomposers (bacteria, fungi). Functional aspects: food chains/webs, energy flow (sunlight → producers → consumers), nutrient (biogeochemical) cycling, and productivity. Influence of ecological factors: e.g. light intensity controls photosynthesis (productivity); temperature affects metabolic rates and dissolved oxygen; nutrient levels affect algal growth (eutrophication if excessive); dissolved oxygen limits animal survival. Thus abiotic factors regulate the structure and functioning of the pond.

ecologypond-ecosystem
4Short answer5 marks

Explain any five ways how microorganisms play an important role in the field of medicine.

Roles of microorganisms in medicine (any five): (1) production of antibiotics (e.g. penicillin from Penicillium, streptomycin from Streptomyces) to treat bacterial infections; (2) production of vaccines (using attenuated/killed microbes) to immunise against diseases; (3) production of vitamins (e.g. B12, riboflavin) and other supplements; (4) production of enzymes and hormones (e.g. insulin via genetically engineered bacteria); (5) production of serums/antitoxins; (6) use in medical research and diagnosis; (7) production of organic acids and probiotics. (Any five.)

microbiologyapplications
5Short answer5 marks

The excessive and unbalanced use of pesticides is a prominent environmental issue in Nepal. Mention any three consequences of overuse of pesticides in your locality and suggest an awareness campaign that you would follow in two points. (3+2)(3+2)

Three consequences of pesticide overuse: (1) soil and water pollution (contamination of drinking water and rivers); (2) harm to non-target organisms — bees, birds, fish, beneficial insects — and loss of biodiversity; (3) bioaccumulation/biomagnification in the food chain causing health hazards (cancer, poisoning) in humans; pesticide residues in food; development of pest resistance.

Awareness campaign (two points): (1) organise community education programmes/posters/street drama on safe use and alternatives (integrated pest management, organic/bio-pesticides); (2) train farmers on correct dosage, protective measures and promotion of organic farming, and lobby for regulation of harmful pesticides.

environmentpesticidesnepal
6Short answer5 marks

What is transverse binary fission? Write its process in Paramecium. (1+2+2)(1+2+2)

Transverse binary fission: An asexual reproduction in which the parent body divides into two equal daughter individuals by a division plane that runs transverse (at right angles) to the longitudinal axis.

Process in Paramecium: (1) The micronucleus divides first by mitosis (amitosis of macronucleus); the macronucleus elongates and divides amitotically. (2) A transverse constriction (furrow) appears at the middle of the body, deepening across the transverse axis. (3) The two contractile vacuoles and other organelles are distributed; new oral grooves form. (4) The body finally divides transversely into two daughter Paramecia, each with a micronucleus and macronucleus, which then grow to full size. It occurs in favourable conditions.

protozoaparameciumbinary-fission
7Short answer5 marks

How can pancreas of a frog play an important role in digestion? Explain it in reference to physiology of intestinal digestion. (2+3)(2+3)

OR

Describe with suitable diagram, how copulation and cocoon formation takes place in earthworm. (2+2+1)(2+2+1)

Pancreas in frog digestion: The pancreas is a mixed gland; its exocrine part secretes pancreatic juice into the duodenum (via the bile-pancreatic duct). Pancreatic juice contains enzymes — trypsin (proteins → peptides/amino acids), amylase (starch → maltose), and lipase (fats → fatty acids + glycerol) — and it is alkaline, neutralising the acidic chyme. Thus in intestinal digestion the pancreas provides the major digestive enzymes that complete the breakdown of carbohydrates, proteins and fats in the small intestine. (The endocrine part secretes insulin/glucagon for blood-sugar regulation.)

OR — Earthworm copulation & cocoon formation: Earthworms are hermaphrodite but cross-fertilise. During copulation two worms come together with their ventral surfaces in opposite directions, held by the clitellum and genital setae; they exchange sperm, which is stored in each other's spermathecae. After separation, the clitellum secretes a mucous cocoon (a girdle) which slides forward over the body; as it passes, it receives ova from the female pores and stored sperm from the spermathecae, where fertilisation occurs. The cocoon then slips off the anterior end, its ends seal, and it is deposited in moist soil where the young develop.

frogdigestionearthworm-reproduction
8Short answer5 marks

How does Darwinism explain the theory of organic evolution? Clarify your answer. (5)(5)

Darwinism (natural selection) explains organic evolution through: (1) overproduction — organisms produce far more offspring than can survive; (2) struggle for existence — limited resources cause competition (intraspecific, interspecific, environmental); (3) variation — individuals show heritable variations; (4) survival of the fittest / natural selection — individuals with favourable variations are better adapted, survive and reproduce, passing on those traits; (5) inheritance and origin of new species — over many generations, accumulation of favourable variations leads to new, better-adapted forms and ultimately new species. Thus nature 'selects' the fittest, driving evolution.

evolutiondarwinism
C

Group 'C'

Give long answer to the following questions.

3 questions·8 marks each
9Long answer8 marks

Why is sexual reproduction important in lower grade plant like fungi? Explain it with respect to sexual reproduction of Yeast along with diagram. (2+2×3)(2+2\times3)

OR

Explain the diagnostic floral characters of family Solanaceae with floral formula and floral diagram. Write the botanical name of any two plants of this family regarding medicinal and edible values. (4+1+1+2)(4+1+1+2)

Importance of sexual reproduction in fungi: it introduces genetic variation (recombination) which aids adaptation and evolution; it restores the diploid phase and produces resistant resting structures (spores) for survival in unfavourable conditions and dispersal.

Sexual reproduction in Yeast: Under unfavourable conditions, two haploid yeast cells (or a cell with a bud) act as gametes; they fuse — plasmogamy (fusion of cytoplasm) followed by karyogamy (fusion of nuclei) — forming a diploid zygote. The diploid nucleus then undergoes meiosis to form four (or eight) haploid ascospores enclosed within the parent cell wall, which now acts as an ascus. On release in favourable conditions, the ascospores germinate into new haploid yeast cells.

OR — Solanaceae: Diagnostic floral characters: flowers bisexual, actinomorphic, hypogynous; calyx 5 sepals (gamosepalous, persistent); corolla 5 petals (gamopetalous); androecium 5 stamens epipetalous; gynoecium bicarpellary, syncarpous, superior ovary with axile placentation, obliquely placed. Floral formula:  \male\female K(5) C(5) A5 G(2)\oplus\ \male\female\ K_{(5)}\ C_{(5)}\ A_5\ \underline{G}_{(2)}. Examples: Solanum tuberosum (potato — edible), Atropa belladonna / Withania somnifera (medicinal); Solanum melongena (brinjal — edible).

fungiyeast-reproductionsolanaceae
10Long answer8 marks

How is excretion performed in earthworm? Explain in analytical approach of the structure of septal nephridia of earthworm with labeled diagram. (1+4+3)(1+4+3)

Excretion in earthworm: carried out by segmentally arranged coiled tubular structures called nephridia (three types: septal, integumentary, pharyngeal). They remove nitrogenous wastes (urea, ammonia) and excess water.

Septal nephridia (structure): located on both sides of the inter-segmental septa from segment 15 backward; each consists of (1) the nephrostome (a ciliated funnel opening into the coelom that draws in coelomic fluid), (2) a short neck, (3) the body of the nephridium — a long twisted tube differentiated into a straight lobe and a twisted loop with ciliated and glandular regions, (4) the terminal duct leading to a common septal excretory canal, which opens through supra-intestinal excretory ducts into the gut (enteronephric type).

Function: coelomic fluid and wastes enter via the nephrostome; as the fluid passes along the tubule, water and useful materials are reabsorbed and nitrogenous wastes are concentrated; the waste is finally discharged into the alimentary canal and expelled with faeces (enteronephric excretion conserves water — an adaptation to terrestrial life).

(Labelled diagram of septal nephridium: nephrostome, neck, body, terminal duct — to be drawn.)

earthwormexcretionnephridia
11Long answer8 marks

Meiosis cell division maintains chromosomal stability in offspring through reduction and disjunction of homologous chromosomes. Two successive steps within this process are given.

Fig-1 and Fig-2: two successive stages of meiosis (chromosomes aligned, then separating)

a. In reference to disjunction, what changes do you find between Fig-1 & Fig-2? Describe it. (4)(4)

b. What had happened in chromosomal stability if changes did not occur from Fig-1 to Fig-2? (1)(1)

c. Draw the diagram of the successive next one step after Fig-2 with two distinguishing features. (1+2)(1+2)

(a) Fig-1 shows Metaphase I — homologous chromosomes (bivalents/tetrads) are arranged in pairs at the equatorial plate, spindle fibres attached. Fig-2 shows Anaphase I — the homologous chromosomes of each bivalent disjoin (separate) and move to opposite poles (whole chromosomes, each still with two chromatids, move apart). The change is the disjunction/segregation of homologous chromosomes, reducing the chromosome number to half (reduction division) and distributing one of each pair to each pole, giving genetic variation.

(b) If disjunction did not occur (non-disjunction), the homologous chromosomes would not separate properly, the gametes would have an abnormal chromosome number (aneuploidy) — chromosomal instability — leading to disorders (e.g. Down's syndrome) and loss of chromosomal stability in offspring.

(c) The next step is Telophase I (followed by cytokinesis): two distinguishing features — (1) chromosomes reach the two opposite poles and a nuclear membrane reforms around each haploid set; (2) the cell divides (cytokinesis) into two haploid daughter cells. (Diagram to be drawn.)

cell-divisionmeiosis

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