Where can I find the FE — Civil FE — Civil question paper 2025?

The full FE — Civil FE — Civil 2025 (Model questions) question paper is available free on Kekkei. You can read every question online and attempt the paper under timed exam conditions.

Does the FE — Civil 2025 paper come with solutions?

Yes. Every question on this FE — Civil past paper includes a step-by-step solution, plus instant AI feedback when you attempt it on Kekkei.

How many marks is the FE — Civil FE — Civil 2025 paper?

The FE — Civil FE — Civil 2025 paper carries 110 full marks and is meant to be completed in 360 minutes, across 10 questions.

Is practising this FE — Civil past paper free?

Yes — reading and attempting this FE — Civil past paper on Kekkei is completely free.

FE — Civil FE — Civil Practice Test 2025

FE — CivilModel questions

110marks

360min

10questions

This is the official FE — Civil FE — Civil question paper for 2025, as set in the Model questions examination. It carries 110 full marks and a time allowance of 360 minutes, across 10 questions. On Kekkei you can attempt this FE — Civil past paper online with a timer, get instant AI feedback and step-by-step solutions, and track the topics where you lose marks — completely free. Whether you are revising for your FE — Civil FE — Civil exam or solving previous years' question papers, this 2025 paper is a great way to practise under real exam conditions.

Level	FE — Civil
Subject	FE — Civil
Year	2025 BS
Exam session	Model questions
Full marks	110
Time allowed	360 minutes
Questions	10, all with step-by-step solutions

Civil Engineering

Select the best answer.

10 questions·1 mark each

1Multiple choice1 mark

A simply supported beam of span $L = 6\,\text{m}$ carries a uniformly distributed load $w = 10\,\text{kN/m}$ . The maximum bending moment at midspan is:

M_{\max} = \frac{wL^2}{8}

a
$30\,\text{kN\cdot m}$
b
$45\,\text{kN\cdot m}$
c
$60\,\text{kN\cdot m}$
d
$90\,\text{kN\cdot m}$

Correct answer: b

$45\,\text{kN\cdot m}$

M_{\max} = \frac{wL^2}{8} = \frac{10 \times 6^2}{8} = \frac{360}{8} = 45\,\text{kN\cdot m}

structural-analysis

2Multiple choice1 mark

A soil sample has a void ratio $e = 0.80$ and a specific gravity of solids $G_s = 2.65$ . The dry unit weight is ( $\gamma_w = 9.81\,\text{kN/m}^3$ ):

\gamma_d = \frac{G_s \gamma_w}{1 + e}

a
$12.5\,\text{kN/m}^3$
b
$14.4\,\text{kN/m}^3$
c
$16.2\,\text{kN/m}^3$
d
$18.0\,\text{kN/m}^3$

Correct answer: b

$14.4\,\text{kN/m}^3$

\gamma_d = \frac{G_s \gamma_w}{1 + e} = \frac{2.65 \times 9.81}{1.80} \approx 14.4\,\text{kN/m}^3

geotechnical

3Multiple choice1 mark

A vehicle traveling at $v = 100\,\text{km/h}$ with perception-reaction time $t_r = 2.5\,\text{s}$ and deceleration $a = 3.4\,\text{m/s}^2$ . The stopping sight distance (SSD) is:

\text{SSD} = v \cdot t_r + \frac{v^2}{2a}

a
$140\,\text{m}$
b
$185\,\text{m}$
c
$210\,\text{m}$
d
$250\,\text{m}$

Correct answer: b

$185\,\text{m}$

Convert $v = 100\,\text{km/h} = 27.78\,\text{m/s}$ .

\text{SSD} = 27.78 \times 2.5 + \frac{27.78^2}{2 \times 3.4} = 69.44 + 113.49 \approx 185\,\text{m}

transportation

4Multiple choice1 mark

Water flows through a pipe with diameter $D = 0.3\,\text{m}$ at velocity $v = 2\,\text{m/s}$ . The volumetric flow rate $Q$ is:

Q = \frac{\pi D^2}{4} \cdot v

a
$0.071\,\text{m}^3/\text{s}$
b
$0.141\,\text{m}^3/\text{s}$
c
$0.283\,\text{m}^3/\text{s}$
d
$0.424\,\text{m}^3/\text{s}$

Correct answer: b

$0.141\,\text{m}^3/\text{s}$

Q = \frac{\pi (0.3)^2}{4} \times 2 = 0.07069 \times 2 = 0.1414\,\text{m}^3/\text{s}

hydraulics

5Multiple choice1 mark

A wastewater treatment plant receives $Q = 5{,}000\,\text{m}^3/\text{day}$ with BOD $C_0 = 200\,\text{mg/L}$ . If 90% BOD removal is achieved, the effluent BOD is:

a
$10\,\text{mg/L}$
b
$20\,\text{mg/L}$
c
$30\,\text{mg/L}$
d
$50\,\text{mg/L}$

Correct answer: b

$20\,\text{mg/L}$

C_{\text{eff}} = 200 \times (1 - 0.90) = 20\,\text{mg/L}

environmental

6Multiple choice1 mark

A surveyor measures 500.00 m with a steel tape at $35^\circ\text{C}$ (standardized at $20^\circ\text{C}$ , $\alpha = 1.17 \times 10^{-5}/^\circ\text{C}$ ). The temperature correction is:

C_t = \alpha \cdot L \cdot (T - T_0)

a
$+0.058\,\text{m}$
b
$+0.088\,\text{m}$
c
$-0.088\,\text{m}$
d
$+0.117\,\text{m}$

Correct answer: b

$+0.088\,\text{m}$

C_t = 1.17 \times 10^{-5} \times 500 \times 15 = 0.08775 \approx +0.088\,\text{m}

surveying

7Multiple choice1 mark

A concrete mix has w/c ratio of 0.45 and uses 350 kg/m\u00b3 of cement. The water content per cubic meter is:

a
$140\,\text{kg/m}^3$
b
$157.5\,\text{kg/m}^3$
c
$175\,\text{kg/m}^3$
d
$200\,\text{kg/m}^3$

Correct answer: b

$157.5\,\text{kg/m}^3$

\text{Water} = 0.45 \times 350 = 157.5\,\text{kg/m}^3

construction

8Multiple choice1 mark

A cantilever beam of length $L = 4\,\text{m}$ with point load $P = 20\,\text{kN}$ at the free end. Maximum deflection ( $EI = 10{,}000\,\text{kN\cdot m}^2$ ):

\delta_{\max} = \frac{PL^3}{3EI}

a
$21.3\,\text{mm}$
b
$42.7\,\text{mm}$
c
$64.0\,\text{mm}$
d
$85.3\,\text{mm}$

Correct answer: b

$42.7\,\text{mm}$

\delta_{\max} = \frac{20 \times 64}{30{,}000} = 0.04267\,\text{m} = 42.7\,\text{mm}

structural-analysis

9Multiple choice1 mark

Water flows from a reservoir through an orifice at depth $h = 5\,\text{m}$ . Theoretical jet velocity ( $g = 9.81\,\text{m/s}^2$ ):

v = \sqrt{2gh}

a
$7.0\,\text{m/s}$
b
$9.9\,\text{m/s}$
c
$12.1\,\text{m/s}$
d
$14.0\,\text{m/s}$

Correct answer: b

$9.9\,\text{m/s}$

v = \sqrt{2 \times 9.81 \times 5} = \sqrt{98.1} \approx 9.9\,\text{m/s}

hydraulics

10Multiple choice1 mark

Ultimate bearing capacity of a strip footing on clay ( $\phi = 0$ ) with $c = 80\,\text{kPa}$ , $N_c = 5.7$ , $\gamma = 18\,\text{kN/m}^3$ , $D_f = 1.0\,\text{m}$ , $N_q = 1.0$ :

q_u = cN_c + \gamma D_f N_q

a
$374\,\text{kPa}$
b
$456\,\text{kPa}$
c
$474\,\text{kPa}$
d
$520\,\text{kPa}$

Correct answer: c

$474\,\text{kPa}$

q_u = 80 \times 5.7 + 18 \times 1.0 \times 1.0 = 456 + 18 = 474\,\text{kPa}

For $\phi = 0$ , $N_\gamma = 0$ .

geotechnical

Frequently asked questions

Where can I find the FE — Civil FE — Civil question paper 2025?: The full FE — Civil FE — Civil 2025 (Model questions) question paper is available free on Kekkei. You can read every question online and attempt the paper under timed exam conditions.
Does the FE — Civil 2025 paper come with solutions?: Yes. Every question on this FE — Civil past paper includes a step-by-step solution, plus instant AI feedback when you attempt it on Kekkei.
How many marks is the FE — Civil FE — Civil 2025 paper?: The FE — Civil FE — Civil 2025 paper carries 110 full marks and is meant to be completed in 360 minutes, across 10 questions.
Is practising this FE — Civil past paper free?: Yes — reading and attempting this FE — Civil past paper on Kekkei is completely free.