Browse papers
A

Section A: Long Answer Questions

Attempt any TWO questions.

3 questions·10 marks each
1long10 marks

Define index numbers. Explain the methods of constructing index numbers (Laspeyres, Paasche, Fisher) and solve a numerical problem using the given price and quantity data.

Index Numbers

Definition. An index number is a statistical measure designed to show changes in a variable (or a group of related variables) such as price, quantity, or value over time, geographically, or against some other characteristic. It is expressed as a percentage relative to a chosen base period taken as 100. Index numbers are sometimes called economic barometers because they measure the relative change in economic activity.

Methods of Constructing Weighted Index Numbers

Let p0,q0p_0, q_0 be the price and quantity in the base year and p1,q1p_1, q_1 in the current year.

1. Laspeyres' Price Index (base-year weights):

P01L=p1q0p0q0×100P_{01}^{L} = \frac{\sum p_1 q_0}{\sum p_0 q_0}\times 100

Uses base-year quantities as weights. It tends to overstate the rise in prices.

2. Paasche's Price Index (current-year weights):

P01P=p1q1p0q1×100P_{01}^{P} = \frac{\sum p_1 q_1}{\sum p_0 q_1}\times 100

Uses current-year quantities as weights. It tends to understate the rise in prices.

3. Fisher's Ideal Index (geometric mean of the two):

P01F=P01L×P01P=p1q0p0q0×p1q1p0q1×100P_{01}^{F} = \sqrt{P^{L}_{01}\times P^{P}_{01}} = \sqrt{\frac{\sum p_1 q_0}{\sum p_0 q_0}\times\frac{\sum p_1 q_1}{\sum p_0 q_1}}\times 100

It is called ideal because it satisfies both the time-reversal and factor-reversal tests.

Numerical Illustration

Commodityp0p_0q0q_0p1p_1q1q_1
A2846
B51065
C414510
D219213

Compute the required sums:

  • p0q0=16+50+56+38=160\sum p_0 q_0 = 16+50+56+38 = 160
  • p1q0=32+60+70+38=200\sum p_1 q_0 = 32+60+70+38 = 200
  • p0q1=12+25+40+26=103\sum p_0 q_1 = 12+25+40+26 = 103
  • p1q1=24+30+50+26=130\sum p_1 q_1 = 24+30+50+26 = 130

Laspeyres: PL=200160×100=125P^{L}=\dfrac{200}{160}\times100 = 125

Paasche: PP=130103×100=126.21P^{P}=\dfrac{130}{103}\times100 = 126.21

Fisher: PF=125×126.21=15776.25=125.60P^{F}=\sqrt{125\times126.21}=\sqrt{15776.25}=125.60

Result. Prices have risen by about 25.6% over the base year (Fisher's ideal index =125.60=125.60).

index-numbers
2long10 marks

Explain the components of a time series. Describe the method of moving averages and the method of least squares for measuring trend.

Components of a Time Series

A time series is a set of observations recorded at successive, usually equally spaced, points of time. Its variations are classified into four components:

  1. Secular Trend (T): the long-term, smooth, general tendency of the data to increase or decrease over a long period (e.g., steady growth in population).
  2. Seasonal Variation (S): regular, periodic fluctuations that complete themselves within a year or less, caused by seasons, customs, or festivals (e.g., higher sales during festivals).
  3. Cyclical Variation (C): wave-like movements lasting more than a year, repeating in oscillating cycles of prosperity, recession, depression, and recovery (the business cycle).
  4. Irregular / Random Variation (I): unpredictable, erratic fluctuations due to chance causes such as floods, strikes, or earthquakes.

These combine in the multiplicative model Y=T×S×C×IY = T\times S\times C\times I or the additive model Y=T+S+C+IY = T+S+C+I.

Method of Moving Averages

This method smooths a series by replacing each value with the average of a fixed number (kk, the period) of surrounding values, thereby averaging out short-term fluctuations and exposing the trend.

For a period kk, the moving average centered at tt is:

Mt=Ytm++Yt++Yt+mkM_t = \frac{Y_{t-m}+\dots+Y_t+\dots+Y_{t+m}}{k}

For an odd period the averages fall against existing time points. For an even period (e.g., 4 yearly), a second 2-period averaging (centering) is applied so values align with the original periods.

Merits: simple, flexible, no rigid assumption about trend shape. Demerits: trend values cannot be obtained for the first and last (k1)/2(k-1)/2 periods; not expressible as a mathematical equation; cannot be used for forecasting.

Method of Least Squares

This fits a mathematical trend line Yc=a+bXY_c = a + bX such that the sum of squared deviations (YYc)2\sum (Y - Y_c)^2 is minimum. The constants are found from the normal equations:

Y=na+bX\sum Y = na + b\sum X XY=aX+bX2\sum XY = a\sum X + b\sum X^2

If the time origin is chosen at the middle so that X=0\sum X = 0, these simplify to:

a=Yn,b=XYX2a = \frac{\sum Y}{n},\qquad b = \frac{\sum XY}{\sum X^2}

Merits: gives a unique, objective trend line usable for forecasting and obtainable for every period. Demerits: rigid (adding new data changes the whole line); assumes a fixed mathematical form for the trend.

time-seriestrend
3long10 marks

Define the binomial and Poisson distributions. Distinguish between them and show that the Poisson distribution is a limiting case of the binomial distribution.

Binomial Distribution

A discrete random variable XX follows the binomial distribution if it counts the number of successes in nn independent Bernoulli trials, each with constant probability of success pp (and q=1pq=1-p). Its probability mass function is:

P(X=x)=(nx)pxqnx,x=0,1,2,,nP(X=x) = \binom{n}{x} p^{x} q^{\,n-x}, \qquad x = 0,1,2,\dots,n

with mean =np= np and variance =npq= npq.

Poisson Distribution

A discrete random variable XX follows the Poisson distribution if it counts the number of occurrences of a rare event in a given interval of time or space, with constant average rate λ\lambda. Its p.m.f. is:

P(X=x)=eλλxx!,x=0,1,2,P(X=x) = \frac{e^{-\lambda}\lambda^{x}}{x!}, \qquad x = 0,1,2,\dots

with mean == variance =λ= \lambda.

Distinction

FeatureBinomialPoisson
Number of trialsfinite nninfinite (large nn)
Parametersn,pn, pλ\lambda
Probability of successfinite, fixed ppvery small (p0p\to 0)
Mean vs variancemean >> variance (np>npqnp > npq)mean == variance =λ=\lambda
Range of XX00 to nn00 to \infty

Poisson as a Limiting Case of the Binomial

Let nn\to\infty and p0p\to 0 such that np=λnp = \lambda remains finite. Then in the binomial p.m.f. substitute p=λ/np = \lambda/n:

P(X=x)=(nx)(λn)x(1λn)nxP(X=x) = \binom{n}{x}\left(\frac{\lambda}{n}\right)^{x}\left(1-\frac{\lambda}{n}\right)^{n-x} =n(n1)(nx+1)x!λxnx(1λn)n(1λn)x= \frac{n(n-1)\cdots(n-x+1)}{x!}\cdot\frac{\lambda^{x}}{n^{x}}\left(1-\frac{\lambda}{n}\right)^{n}\left(1-\frac{\lambda}{n}\right)^{-x}

Group the terms:

=λxx!n(n1)(nx+1)nx1(1λn)neλ(1λn)x1= \frac{\lambda^{x}}{x!}\cdot\underbrace{\frac{n(n-1)\cdots(n-x+1)}{n^{x}}}_{\to\,1}\cdot\underbrace{\left(1-\frac{\lambda}{n}\right)^{n}}_{\to\, e^{-\lambda}}\cdot\underbrace{\left(1-\frac{\lambda}{n}\right)^{-x}}_{\to\,1}

As nn\to\infty: the first factor 1\to 1, (1λn)neλ\left(1-\frac{\lambda}{n}\right)^{n}\to e^{-\lambda}, and the last factor 1\to 1. Therefore:

limnP(X=x)=eλλxx!\lim_{n\to\infty} P(X=x) = \frac{e^{-\lambda}\lambda^{x}}{x!}

which is the Poisson distribution. Hence the Poisson is the limiting form of the binomial when nn is large, pp is small, and np=λnp=\lambda is moderate.

binomialpoisson
B

Section B: Short Answer Questions

Attempt any EIGHT questions.

9 questions·5 marks each
4short5 marks

Define index numbers.

An index number is a specialized statistical measure that expresses the relative change in the magnitude of a variable (or group of variables) — such as price, quantity, or value — over time or space, with respect to a chosen base period taken as 100. For example, a price index of 125 means prices have risen 25% above the base period. Because they summarize economic change, index numbers are often called economic barometers. They are typically computed as I01=p1p0×100I_{01}=\dfrac{\sum p_1}{\sum p_0}\times 100 (simple aggregative) or by weighted methods.

index-numbers
5short5 marks

What are the components of a time series?

A time series has four components:

  1. Secular Trend (T): the long-term general tendency of the data to rise or fall over a long period.
  2. Seasonal Variation (S): regular, short-term periodic fluctuations completing within a year (due to seasons, festivals, customs).
  3. Cyclical Variation (C): wave-like oscillations spread over more than a year (business cycles of boom and slump).
  4. Irregular / Random Variation (I): unpredictable fluctuations caused by chance events (floods, strikes, wars).

They combine as Y=T×S×C×IY = T\times S\times C\times I (multiplicative) or Y=T+S+C+IY = T+S+C+I (additive).

time-series
6short5 marks

State Fisher's ideal index number formula.

Fisher's Ideal Index is the geometric mean of the Laspeyres and Paasche index numbers:

P01F=P01L×P01P=p1q0p0q0×p1q1p0q1×100P_{01}^{F} = \sqrt{P^{L}_{01}\times P^{P}_{01}} = \sqrt{\frac{\sum p_1 q_0}{\sum p_0 q_0}\times\frac{\sum p_1 q_1}{\sum p_0 q_1}}\times 100

where p0,q0p_0,q_0 are base-year price and quantity and p1,q1p_1,q_1 are current-year price and quantity. It is called ideal because it uses both base- and current-year weights and satisfies the time-reversal test (P01×P10=1P_{01}\times P_{10}=1) and the factor-reversal test (P01×Q01=p1q1p0q0P_{01}\times Q_{01}=\dfrac{\sum p_1 q_1}{\sum p_0 q_0}).

index-numbers
7short5 marks

What is the method of moving averages?

The method of moving averages is a technique for measuring the trend of a time series by smoothing out short-term fluctuations. Each observation is replaced by the arithmetic mean of a fixed number kk of consecutive values (the period of the moving average):

Mt=Ytm++Yt++Yt+mkM_t = \frac{Y_{t-m}+\cdots+Y_t+\cdots+Y_{t+m}}{k}

When kk is odd, the averages line up directly with existing time points. When kk is even, a further 2-item averaging (centering) is done so values align with original periods. As the period increases, the smoothed series shows the trend more clearly.

Limitations: trend values are lost for the first and last few periods, it gives no equation, and it cannot be used for forecasting.

time-series
8short5 marks

Distinguish between binomial and Poisson distributions.

BasisBinomial DistributionPoisson Distribution
NatureFinite, fixed number nn of trialsNumber of trials infinite/very large
ParametersTwo: nn and ppOne: λ\lambda (mean)
Success probabilityFinite and constant ppVery small, p0p\to 0
p.m.f.(nx)pxqnx\binom{n}{x}p^{x}q^{n-x}eλλxx!\dfrac{e^{-\lambda}\lambda^{x}}{x!}
Mean & varianceMean =np=np, Variance =npq=npq; mean > varianceMean == Variance =λ=\lambda
Range of XX0,1,,n0,1,\dots,n0,1,2,,0,1,2,\dots,\infty
UseRepeated fixed trials (coin tosses, defectives in a lot of nn)Rare events per unit time/space (accidents, typing errors)

The Poisson is the limiting case of the binomial when nn\to\infty, p0p\to0, with np=λnp=\lambda finite.

distribution
9short5 marks

Define the mean and variance of the binomial distribution.

For a binomial distribution with nn independent trials and success probability pp (with q=1pq=1-p), the probability mass function is P(X=x)=(nx)pxqnxP(X=x)=\binom{n}{x}p^{x}q^{n-x}.

Mean:

E(X)=μ=npE(X) = \mu = np

Variance:

Var(X)=σ2=npq=np(1p)\operatorname{Var}(X) = \sigma^{2} = npq = np(1-p)

The standard deviation is σ=npq\sigma=\sqrt{npq}. Since 0<q<10<q<1, the variance npqnpq is always less than the mean npnp; that is, for the binomial distribution mean > variance.

binomial
10short5 marks

What is a secular trend?

A secular trend (or simply trend) is the smooth, regular, long-term movement of a time series that shows the general tendency of the data to increase, decrease, or remain stable over a long period of time. It reflects the cumulative effect of persistent forces such as population growth, technological change, or improved productivity, rather than short-term seasonal or random factors.

For example, a steady rise in a country's population or GDP over several decades is a secular trend. It can be measured by the freehand (graphic) method, the method of moving averages, the method of semi-averages, or the method of least squares.

time-series
11short5 marks

Define Laspeyres and Paasche index numbers.

Both are weighted aggregative price index numbers. Let p0,q0p_0,q_0 be base-year price and quantity and p1,q1p_1,q_1 be current-year price and quantity.

Laspeyres' Index (base-year quantities as weights):

P01L=p1q0p0q0×100P_{01}^{L} = \frac{\sum p_1 q_0}{\sum p_0 q_0}\times 100

It measures the change in cost of buying the base-year basket at current prices and tends to overstate price rise.

Paasche's Index (current-year quantities as weights):

P01P=p1q1p0q1×100P_{01}^{P} = \frac{\sum p_1 q_1}{\sum p_0 q_1}\times 100

It measures the change in cost of the current-year basket and tends to understate price rise.

The geometric mean of the two gives Fisher's ideal index.

index-numbers
12short5 marks

Find the mean of the binomial distribution with n = 10, p = 0.4.

For a binomial distribution, the mean is μ=np\mu = np.

Given n=10n = 10 and p=0.4p = 0.4:

μ=np=10×0.4=4\mu = np = 10 \times 0.4 = 4

The mean of the distribution is 4.

(For completeness, the variance is σ2=npq=10×0.4×0.6=2.4\sigma^2 = npq = 10\times0.4\times0.6 = 2.4.)

binomial

Frequently asked questions

Where can I find the BSc CSIT (TU) Statistics I (BSc CSIT, STA164) question paper 2081?
The full BSc CSIT (TU) Statistics I (BSc CSIT, STA164) 2081 (regular) question paper is available free on Kekkei. You can read every question online and attempt the paper under timed exam conditions.
Does the Statistics I (BSc CSIT, STA164) 2081 paper come with solutions?
Yes. Every question on this Statistics I (BSc CSIT, STA164) past paper includes a step-by-step solution, plus instant AI feedback when you attempt it on Kekkei.
How many marks is the BSc CSIT (TU) Statistics I (BSc CSIT, STA164) 2081 paper?
The BSc CSIT (TU) Statistics I (BSc CSIT, STA164) 2081 paper carries 60 full marks and is meant to be completed in 180 minutes, across 12 questions.
Is practising this Statistics I (BSc CSIT, STA164) past paper free?
Yes — reading and attempting this Statistics I (BSc CSIT, STA164) past paper on Kekkei is completely free.