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Section A: Long Answer Questions

Attempt any TWO questions.

3 questions·10 marks each
1long10 marks

What is diffraction grating? Derive the grating equation and explain how it is used to determine the wavelength of light.

Diffraction Grating

A diffraction grating is an optical component consisting of a large number of equidistant, parallel slits (or rulings) of equal width ruled on a transparent or reflecting surface. If aa is the width of each transparent slit and bb the width of each opaque space, the quantity (a+b)(a+b) is called the grating element (or grating constant).

Derivation of the Grating Equation

Consider a plane wavefront of monochromatic light of wavelength λ\lambda incident normally on a grating. Light diffracted at an angle θ\theta from successive slits is brought to focus by a lens. The path difference between rays from two consecutive corresponding points (separated by the grating element) is:

Δ=(a+b)sinθ\Delta = (a+b)\sin\theta

For constructive interference (principal maxima), this path difference must be an integral multiple of the wavelength:

(a+b)sinθ=nλn=0,1,2,(a+b)\sin\theta = n\lambda \qquad n = 0,1,2,\dots

This is the grating equation, where nn is the order of the spectrum. If N=1a+bN = \dfrac{1}{a+b} is the number of lines per unit length of the grating, then:

sinθ=Nnλ\sin\theta = N\, n\, \lambda

Determination of Wavelength of Light

  1. The grating is mounted on the prism table of a spectrometer with its plane normal to the incident parallel beam from the collimator.
  2. The grating element (a+b)(a+b) is found from the known number of lines per cm ruled by the manufacturer: (a+b)=1N(a+b)=\dfrac{1}{N}.
  3. The telescope is rotated to locate a spectral line of a chosen order nn, and the angle of diffraction θ\theta is measured accurately using the vernier scales.
  4. The wavelength is then computed from:
λ=(a+b)sinθn\lambda = \frac{(a+b)\sin\theta}{n}

By measuring θ\theta for several orders and taking the mean, the wavelength of the light is determined precisely.

diffraction
2long10 marks

Derive the expression for the energy stored in a charged capacitor and the energy density of an electric field.

Energy Stored in a Charged Capacitor

Consider a capacitor of capacitance CC being charged. Let qq be the charge on it at some instant and V=q/CV=q/C the corresponding potential difference. To transfer an additional small charge dqdq against this potential, the work done is:

dW=Vdq=qCdqdW = V\,dq = \frac{q}{C}\,dq

The total work done in charging the capacitor from 00 to a final charge QQ is:

W=0QqCdq=1CQ22=Q22CW = \int_0^Q \frac{q}{C}\,dq = \frac{1}{C}\cdot\frac{Q^2}{2} = \frac{Q^2}{2C}

This work is stored as electrostatic potential energy UU. Using Q=CVQ = CV, the energy stored can be written in three equivalent forms:

U=Q22C=12CV2=12QV\boxed{U = \frac{Q^2}{2C} = \frac{1}{2}CV^2 = \frac{1}{2}QV}

Energy Density of the Electric Field

Consider a parallel-plate capacitor with plate area AA and separation dd. Its capacitance is:

C=ε0AdC = \frac{\varepsilon_0 A}{d}

If EE is the uniform field between the plates, the potential difference is V=EdV = Ed. Substituting in U=12CV2U = \tfrac{1}{2}CV^2:

U=12ε0Ad(Ed)2=12ε0E2(Ad)U = \frac{1}{2}\cdot\frac{\varepsilon_0 A}{d}\,(Ed)^2 = \frac{1}{2}\varepsilon_0 E^2 (Ad)

Since AdAd is the volume of the region containing the field, the energy per unit volume (energy density) is:

u=UAd=12ε0E2\boxed{u = \frac{U}{Ad} = \frac{1}{2}\varepsilon_0 E^2}

This shows that energy is stored in the electric field itself, with a density proportional to the square of the field strength. (In a dielectric medium of permittivity ε\varepsilon, u=12εE2u = \tfrac{1}{2}\varepsilon E^2.)

capacitance
3long10 marks

Discuss the formation of Newton's rings. Derive expressions for the diameters of bright and dark rings and explain how the wavelength of light is determined.

Formation of Newton's Rings

When a plano-convex lens of large radius of curvature is placed with its convex surface on a flat glass plate, a thin air film of gradually increasing thickness is formed between them. When monochromatic light falls normally on this arrangement, light reflected from the top and bottom surfaces of the air film interferes. The locus of points of equal film thickness are concentric circles, so the interference fringes appear as alternate bright and dark concentric rings with a dark spot at the centre. These are called Newton's rings.

The condition for interference in a thin film of air (μ=1\mu = 1) at normal incidence, including the extra phase change of π\pi on reflection at the glass surface, gives:

  • Dark ring: 2t=nλ2t = n\lambda
  • Bright ring: 2t=(n+12)λ2t = \left(n+\tfrac{1}{2}\right)\lambda

Diameters of the Rings

Let RR be the radius of curvature of the lens and rr the radius of a ring where the film thickness is tt. By the geometry of the circle (chord property):

r2=2Rtt=r22Rr^2 = 2Rt \quad\Rightarrow\quad t = \frac{r^2}{2R}

Dark rings: Using 2t=nλ2t = n\lambda,

rn2R=nλ    rn2=nRλ\frac{r_n^2}{R} = n\lambda \;\Rightarrow\; r_n^2 = nR\lambda

With diameter Dn=2rnD_n = 2r_n:

Dn2=4nRλDnn\boxed{D_n^2 = 4nR\lambda} \quad\Rightarrow\quad D_n \propto \sqrt{n}

Bright rings: Using 2t=(n+12)λ2t = (n+\tfrac12)\lambda,

Dn2=2(2n1)RλDn2n1\boxed{D_n^2 = 2(2n-1)R\lambda} \quad\Rightarrow\quad D_n \propto \sqrt{2n-1}

Thus the diameters of dark rings are proportional to the square roots of natural numbers, and of bright rings to the square roots of odd numbers.

Determination of Wavelength

For dark rings, Dn2=4nRλD_n^2 = 4nR\lambda. Taking two different rings, the nn-th and mm-th:

Dn2Dm2=4(nm)RλD_n^2 - D_m^2 = 4(n-m)R\lambda

Therefore:

λ=Dn2Dm24(nm)R\boxed{\lambda = \frac{D_n^2 - D_m^2}{4(n-m)R}}

The diameters Dn,DmD_n, D_m are measured with a travelling microscope, RR is found separately (e.g. with a spherometer), and λ\lambda is computed. Taking the difference eliminates errors due to imperfect contact at the centre.

interference
B

Section B: Short Answer Questions

Attempt any EIGHT questions.

9 questions·5 marks each
4short5 marks

State Huygens' principle.

Huygens' Principle states that:

  1. Every point on a given wavefront acts as a fresh source of secondary wavelets, which spread out in all forward directions with the speed of the wave in the medium.
  2. The new position of the wavefront after a time tt is given by the forward common tangent (envelope) to all these secondary wavelets.

This principle geometrically explains the propagation of waves and accounts for reflection, refraction, and diffraction of light.

wave-optics
5short5 marks

Derive the relation between electric field and potential.

Relation Between Electric Field and Potential

Consider a charge q0q_0 moved through a small displacement dld\vec{l} in an electric field E\vec{E}. The work done by the field is dW=q0EdldW = q_0\vec{E}\cdot d\vec{l}. The change in potential energy is dU=dWdU = -dW, and since potential V=U/q0V = U/q_0:

dV=EdldV = -\vec{E}\cdot d\vec{l}

For a displacement along the xx-direction this gives the component of the field as the negative gradient of potential:

Ex=dVdxE_x = -\frac{dV}{dx}

In three dimensions, generalising over all directions:

E=V=(Vxi^+Vyj^+Vzk^)\boxed{\vec{E} = -\nabla V = -\left(\frac{\partial V}{\partial x}\hat{i} + \frac{\partial V}{\partial y}\hat{j} + \frac{\partial V}{\partial z}\hat{k}\right)}

Thus the electric field equals the negative potential gradient. The negative sign shows that the field points in the direction of decreasing potential, and its magnitude equals the rate of change of potential with distance (units: V/m).

electrostatics
6short5 marks

Explain Ampere's circuital law.

Ampere's Circuital Law

Statement: The line integral of the magnetic field B\vec{B} around any closed loop is equal to μ0\mu_0 times the total (net) current IencI_{enc} enclosed by that loop.

Bdl=μ0Ienc\oint \vec{B}\cdot d\vec{l} = \mu_0 I_{enc}

where μ0=4π×107 T\cdotpm/A\mu_0 = 4\pi\times10^{-7}\ \text{T·m/A} is the permeability of free space.

Explanation / Example: For an infinitely long straight wire carrying current II, choose a circular Amperian loop of radius rr concentric with the wire. By symmetry BB is constant along the loop and parallel to dld\vec{l}, so:

Bdl=B(2πr)=μ0IB=μ0I2πr\oint \vec{B}\cdot d\vec{l} = B(2\pi r) = \mu_0 I \quad\Rightarrow\quad B = \frac{\mu_0 I}{2\pi r}

Ampere's law is the magnetic analogue of Gauss's law and is most useful for computing fields in highly symmetric situations (long wire, solenoid, toroid). Maxwell later generalised it by adding the displacement-current term μ0ε0dΦE/dt\mu_0\varepsilon_0\,d\Phi_E/dt to make it valid for time-varying fields.

magnetism
7short5 marks

Distinguish between single-mode and multi-mode optical fibers.

Single-mode vs Multi-mode Optical Fibers

FeatureSingle-mode fiberMulti-mode fiber
Core diameterVery small, 8\approx 810 μm10\ \mu mLarge, 50\approx 50100 μm100\ \mu m
Number of modesAllows only one mode of propagationSupports many modes simultaneously
Modal dispersionNegligible (no intermodal dispersion)Significant — causes pulse broadening
Bandwidth / data rateVery high; long-distance, high capacityLower; suited for short distances
Light sourceLaser diode (coherent)LED or laser is acceptable
Cost & couplingCostlier, harder to splice/coupleCheaper, easier to launch light
Typical useLong-haul telecom, undersea cablesLAN, short links within a building

Summary: A single-mode fiber has a narrow core that confines light to a single path, giving very low dispersion and high bandwidth over long distances, whereas a multi-mode fiber has a wider core allowing many paths, which is cheaper but limited by modal dispersion to shorter links.

optical-fiber
8short5 marks

Define damped harmonic oscillation and write its equation.

Damped Harmonic Oscillation

Definition: A damped harmonic oscillation is a periodic motion in which the amplitude of vibration decreases gradually with time because the oscillating system continuously loses energy to a resistive (frictional/viscous) force. This damping force is generally proportional to the velocity of the body, Fd=bdxdtF_d = -b\dfrac{dx}{dt}, where bb is the damping constant.

Equation of motion: Combining the restoring force kx-kx and the damping force bx˙-b\,\dot{x}, Newton's second law gives:

md2xdt2=kxbdxdtm\frac{d^2x}{dt^2} = -kx - b\frac{dx}{dt} d2xdt2+2γdxdt+ω02x=0\boxed{\frac{d^2x}{dt^2} + 2\gamma\frac{dx}{dt} + \omega_0^2 x = 0}

where 2γ=b/m2\gamma = b/m (damping coefficient) and ω02=k/m\omega_0^2 = k/m is the natural angular frequency.

For the under-damped case (γ<ω0\gamma < \omega_0) the solution is:

x(t)=A0eγtcos(ωt+ϕ),ω=ω02γ2x(t) = A_0 e^{-\gamma t}\cos(\omega' t + \phi), \qquad \omega' = \sqrt{\omega_0^2 - \gamma^2}

The factor eγte^{-\gamma t} shows the exponential decay of amplitude with time.

oscillations
9short5 marks

State Gauss's law in dielectrics.

Gauss's Law in Dielectrics

In the presence of a dielectric, both free charges and bound (polarisation) charges contribute to the field. To handle this, the electric displacement vector D=ε0E+P\vec{D} = \varepsilon_0\vec{E} + \vec{P} is introduced, where P\vec{P} is the polarisation.

Statement: The surface integral of the electric displacement D\vec{D} over any closed surface equals the total free charge qfreeq_{free} enclosed by that surface (bound charges do not appear):

DdA=qfree\boxed{\oint \vec{D}\cdot d\vec{A} = q_{free}}

Equivalently, in terms of the field E\vec{E} in a linear dielectric of permittivity ε=ε0εr\varepsilon = \varepsilon_0\varepsilon_r:

EdA=qfreeε0εr\oint \vec{E}\cdot d\vec{A} = \frac{q_{free}}{\varepsilon_0\varepsilon_r}

Thus the law shows that inside a dielectric the field is reduced by the factor εr\varepsilon_r (the relative permittivity) compared with vacuum, because of the opposing field produced by induced bound charges.

electrostatics
10short5 marks

What are the properties of laser light?

Properties of Laser Light

Laser (Light Amplification by Stimulated Emission of Radiation) light has the following characteristic properties:

  1. Monochromaticity — It is highly single-coloured, consisting of essentially one wavelength (very narrow spectral linewidth).
  2. Coherence — All the waves are in phase, both spatially and temporally, because they arise from stimulated emission. This gives a constant phase relationship.
  3. Directionality — The beam is highly collimated and travels in a single, well-defined direction with very little angular spread (low divergence).
  4. High Intensity / Brightness — Because the energy is concentrated into a narrow, parallel beam of one wavelength, the intensity is extremely high.
  5. Low Divergence — The beam remains narrow even over long distances.

These properties arise from the process of stimulated emission in a medium with a population inversion inside an optical resonator.

laser
11short5 marks

Explain the working of a step-index fiber.

Working of a Step-Index Optical Fiber

A step-index fiber consists of a cylindrical central core of uniform (constant) refractive index n1n_1, surrounded by a cladding of slightly lower refractive index n2n_2 (n1>n2n_1 > n_2). The refractive index changes abruptly (in a step) at the core–cladding boundary — hence the name.

Principle of operation — Total Internal Reflection (TIR): Light launched into the core at an angle within the acceptance cone strikes the core–cladding interface at an angle greater than the critical angle θc\theta_c, where:

sinθc=n2n1\sin\theta_c = \frac{n_2}{n_1}

The ray is therefore totally internally reflected repeatedly and is guided along the length of the fiber with very little loss, zig-zagging down the core.

The light-gathering capacity is described by the numerical aperture:

NA=sinθa=n12n22NA = \sin\theta_a = \sqrt{n_1^2 - n_2^2}

where θa\theta_a is the maximum acceptance angle. Only rays entering within this cone are guided. In a multimode step-index fiber different rays take paths of different lengths, causing modal dispersion (pulse broadening), which limits its bandwidth.

optical-fiber
12short5 marks

Write short notes on the resolving power of a grating.

Resolving Power of a Grating

The resolving power of a diffraction grating is its ability to separate two spectral lines of nearly equal wavelengths λ\lambda and λ+dλ\lambda + d\lambda that are just distinguishable as separate. It is defined quantitatively as:

R=λdλR = \frac{\lambda}{d\lambda}

Expression: Applying the Rayleigh criterion to the grating equation (a+b)sinθ=nλ(a+b)\sin\theta = n\lambda, the resolving power of a grating is found to be:

R=λdλ=nN\boxed{R = \frac{\lambda}{d\lambda} = nN}

where

  • nn = order of the spectrum, and
  • NN = total number of lines (rulings) illuminated on the grating.

Key points:

  • Resolving power is independent of the grating element; it depends only on the total number of lines used and the order.
  • It increases with higher orders (nn) and with a larger illuminated width (more lines NN).
  • Hence a wide grating with many rulings observed in a high order gives the best resolution of closely spaced spectral lines.
diffraction

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