BSc CSIT (TU) Science Physics (BSc CSIT, PHY113) Question Paper 2075 Nepal
This is the official BSc CSIT (TU) (Science stream) Physics (BSc CSIT, PHY113) question paper for 2075, as set in the regular annual examination. It carries 60 full marks and a time allowance of 180 minutes, across 12 questions. On Kekkei you can attempt this Physics (BSc CSIT, PHY113) past paper online with a timer, get instant AI feedback and step-by-step solutions, and track the topics where you lose marks — completely free. Whether you are revising for your BSc CSIT (TU) Physics (BSc CSIT, PHY113) exam or solving previous years' question papers, this 2075 paper is a great way to practise under real exam conditions.
Section A: Long Answer Questions
Attempt any TWO questions.
What is diffraction grating? Derive the grating equation and explain how it is used to determine the wavelength of light.
Diffraction Grating
A diffraction grating is an optical component consisting of a large number of equidistant, parallel slits (or rulings) of equal width ruled on a transparent or reflecting surface. If is the width of each transparent slit and the width of each opaque space, the quantity is called the grating element (or grating constant).
Derivation of the Grating Equation
Consider a plane wavefront of monochromatic light of wavelength incident normally on a grating. Light diffracted at an angle from successive slits is brought to focus by a lens. The path difference between rays from two consecutive corresponding points (separated by the grating element) is:
For constructive interference (principal maxima), this path difference must be an integral multiple of the wavelength:
This is the grating equation, where is the order of the spectrum. If is the number of lines per unit length of the grating, then:
Determination of Wavelength of Light
- The grating is mounted on the prism table of a spectrometer with its plane normal to the incident parallel beam from the collimator.
- The grating element is found from the known number of lines per cm ruled by the manufacturer: .
- The telescope is rotated to locate a spectral line of a chosen order , and the angle of diffraction is measured accurately using the vernier scales.
- The wavelength is then computed from:
By measuring for several orders and taking the mean, the wavelength of the light is determined precisely.
Derive the expression for the energy stored in a charged capacitor and the energy density of an electric field.
Energy Stored in a Charged Capacitor
Consider a capacitor of capacitance being charged. Let be the charge on it at some instant and the corresponding potential difference. To transfer an additional small charge against this potential, the work done is:
The total work done in charging the capacitor from to a final charge is:
This work is stored as electrostatic potential energy . Using , the energy stored can be written in three equivalent forms:
Energy Density of the Electric Field
Consider a parallel-plate capacitor with plate area and separation . Its capacitance is:
If is the uniform field between the plates, the potential difference is . Substituting in :
Since is the volume of the region containing the field, the energy per unit volume (energy density) is:
This shows that energy is stored in the electric field itself, with a density proportional to the square of the field strength. (In a dielectric medium of permittivity , .)
Discuss the formation of Newton's rings. Derive expressions for the diameters of bright and dark rings and explain how the wavelength of light is determined.
Formation of Newton's Rings
When a plano-convex lens of large radius of curvature is placed with its convex surface on a flat glass plate, a thin air film of gradually increasing thickness is formed between them. When monochromatic light falls normally on this arrangement, light reflected from the top and bottom surfaces of the air film interferes. The locus of points of equal film thickness are concentric circles, so the interference fringes appear as alternate bright and dark concentric rings with a dark spot at the centre. These are called Newton's rings.
The condition for interference in a thin film of air () at normal incidence, including the extra phase change of on reflection at the glass surface, gives:
- Dark ring:
- Bright ring:
Diameters of the Rings
Let be the radius of curvature of the lens and the radius of a ring where the film thickness is . By the geometry of the circle (chord property):
Dark rings: Using ,
With diameter :
Bright rings: Using ,
Thus the diameters of dark rings are proportional to the square roots of natural numbers, and of bright rings to the square roots of odd numbers.
Determination of Wavelength
For dark rings, . Taking two different rings, the -th and -th:
Therefore:
The diameters are measured with a travelling microscope, is found separately (e.g. with a spherometer), and is computed. Taking the difference eliminates errors due to imperfect contact at the centre.
Section B: Short Answer Questions
Attempt any EIGHT questions.
State Huygens' principle.
Huygens' Principle states that:
- Every point on a given wavefront acts as a fresh source of secondary wavelets, which spread out in all forward directions with the speed of the wave in the medium.
- The new position of the wavefront after a time is given by the forward common tangent (envelope) to all these secondary wavelets.
This principle geometrically explains the propagation of waves and accounts for reflection, refraction, and diffraction of light.
Derive the relation between electric field and potential.
Relation Between Electric Field and Potential
Consider a charge moved through a small displacement in an electric field . The work done by the field is . The change in potential energy is , and since potential :
For a displacement along the -direction this gives the component of the field as the negative gradient of potential:
In three dimensions, generalising over all directions:
Thus the electric field equals the negative potential gradient. The negative sign shows that the field points in the direction of decreasing potential, and its magnitude equals the rate of change of potential with distance (units: V/m).
Explain Ampere's circuital law.
Ampere's Circuital Law
Statement: The line integral of the magnetic field around any closed loop is equal to times the total (net) current enclosed by that loop.
where is the permeability of free space.
Explanation / Example: For an infinitely long straight wire carrying current , choose a circular Amperian loop of radius concentric with the wire. By symmetry is constant along the loop and parallel to , so:
Ampere's law is the magnetic analogue of Gauss's law and is most useful for computing fields in highly symmetric situations (long wire, solenoid, toroid). Maxwell later generalised it by adding the displacement-current term to make it valid for time-varying fields.
Distinguish between single-mode and multi-mode optical fibers.
Single-mode vs Multi-mode Optical Fibers
| Feature | Single-mode fiber | Multi-mode fiber |
|---|---|---|
| Core diameter | Very small, – | Large, – |
| Number of modes | Allows only one mode of propagation | Supports many modes simultaneously |
| Modal dispersion | Negligible (no intermodal dispersion) | Significant — causes pulse broadening |
| Bandwidth / data rate | Very high; long-distance, high capacity | Lower; suited for short distances |
| Light source | Laser diode (coherent) | LED or laser is acceptable |
| Cost & coupling | Costlier, harder to splice/couple | Cheaper, easier to launch light |
| Typical use | Long-haul telecom, undersea cables | LAN, short links within a building |
Summary: A single-mode fiber has a narrow core that confines light to a single path, giving very low dispersion and high bandwidth over long distances, whereas a multi-mode fiber has a wider core allowing many paths, which is cheaper but limited by modal dispersion to shorter links.
Define damped harmonic oscillation and write its equation.
Damped Harmonic Oscillation
Definition: A damped harmonic oscillation is a periodic motion in which the amplitude of vibration decreases gradually with time because the oscillating system continuously loses energy to a resistive (frictional/viscous) force. This damping force is generally proportional to the velocity of the body, , where is the damping constant.
Equation of motion: Combining the restoring force and the damping force , Newton's second law gives:
where (damping coefficient) and is the natural angular frequency.
For the under-damped case () the solution is:
The factor shows the exponential decay of amplitude with time.
State Gauss's law in dielectrics.
Gauss's Law in Dielectrics
In the presence of a dielectric, both free charges and bound (polarisation) charges contribute to the field. To handle this, the electric displacement vector is introduced, where is the polarisation.
Statement: The surface integral of the electric displacement over any closed surface equals the total free charge enclosed by that surface (bound charges do not appear):
Equivalently, in terms of the field in a linear dielectric of permittivity :
Thus the law shows that inside a dielectric the field is reduced by the factor (the relative permittivity) compared with vacuum, because of the opposing field produced by induced bound charges.
What are the properties of laser light?
Properties of Laser Light
Laser (Light Amplification by Stimulated Emission of Radiation) light has the following characteristic properties:
- Monochromaticity — It is highly single-coloured, consisting of essentially one wavelength (very narrow spectral linewidth).
- Coherence — All the waves are in phase, both spatially and temporally, because they arise from stimulated emission. This gives a constant phase relationship.
- Directionality — The beam is highly collimated and travels in a single, well-defined direction with very little angular spread (low divergence).
- High Intensity / Brightness — Because the energy is concentrated into a narrow, parallel beam of one wavelength, the intensity is extremely high.
- Low Divergence — The beam remains narrow even over long distances.
These properties arise from the process of stimulated emission in a medium with a population inversion inside an optical resonator.
Explain the working of a step-index fiber.
Working of a Step-Index Optical Fiber
A step-index fiber consists of a cylindrical central core of uniform (constant) refractive index , surrounded by a cladding of slightly lower refractive index (). The refractive index changes abruptly (in a step) at the core–cladding boundary — hence the name.
Principle of operation — Total Internal Reflection (TIR): Light launched into the core at an angle within the acceptance cone strikes the core–cladding interface at an angle greater than the critical angle , where:
The ray is therefore totally internally reflected repeatedly and is guided along the length of the fiber with very little loss, zig-zagging down the core.
The light-gathering capacity is described by the numerical aperture:
where is the maximum acceptance angle. Only rays entering within this cone are guided. In a multimode step-index fiber different rays take paths of different lengths, causing modal dispersion (pulse broadening), which limits its bandwidth.
Write short notes on the resolving power of a grating.
Resolving Power of a Grating
The resolving power of a diffraction grating is its ability to separate two spectral lines of nearly equal wavelengths and that are just distinguishable as separate. It is defined quantitatively as:
Expression: Applying the Rayleigh criterion to the grating equation , the resolving power of a grating is found to be:
where
- = order of the spectrum, and
- = total number of lines (rulings) illuminated on the grating.
Key points:
- Resolving power is independent of the grating element; it depends only on the total number of lines used and the order.
- It increases with higher orders () and with a larger illuminated width (more lines ).
- Hence a wide grating with many rulings observed in a high order gives the best resolution of closely spaced spectral lines.
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