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A

Section A: Long Answer Questions

Attempt all / any as specified.

4 questions
1long14 marks

(a) With the help of a functional block diagram, describe the generalized configuration of a measurement system, clearly explaining the role of the primary sensing element, variable conversion element, variable manipulation element, data transmission element and data presentation element. [8]

(b) Define accuracy, precision, resolution and sensitivity of an instrument. Distinguish between accuracy and precision with a suitable target-diagram illustration. [6]

(a) Generalized Configuration of a Measurement System [8]

A measurement system is conventionally divided into five functional stages. The signal (measurand) flows from left to right:

 Measurand --> [Primary    ] --> [Variable    ] --> [Variable    ] --> [Data        ] --> [Data         ]
              [Sensing    ]     [Conversion  ]     [Manipulation]     [Transmission ]     [Presentation ]
              [Element    ]     [Element     ]     [Element      ]     [Element      ]     [Element       ]

1. Primary Sensing Element The element that first receives energy from the measured medium and produces an output dependent on the measurand. It is the transducer/sensor in direct contact with the quantity being measured. Example: a thermocouple junction sensing temperature, a Bourdon tube sensing pressure.

2. Variable Conversion Element Converts the output of the primary sensing element into a more suitable variable (usually electrical) while preserving the information. Example: an LVDT converting mechanical displacement of a Bourdon tube into a voltage.

3. Variable Manipulation Element Manipulates (changes the magnitude of) the signal without changing its physical nature — i.e. amplification, attenuation, linearization or filtering. Example: an amplifier raising a low-level mV signal to a usable level.

4. Data Transmission Element Carries the signal from one location to another, e.g. from the field to the control room. Example: cables, telemetry links, 4–20 mA current loop.

5. Data Presentation Element Conveys the processed information to a human observer or to a recording/control device in a readable form. Example: a moving-pointer scale, digital display, chart recorder or CRT/monitor.

(b) Accuracy, Precision, Resolution, Sensitivity [6]

  • Accuracy: the closeness of a measured value to the true (accepted) value of the quantity. Usually expressed as a percentage of full-scale deflection.
  • Precision (repeatability): the closeness of agreement among a set of repeated measurements of the same quantity under the same conditions. It describes reproducibility, not correctness.
  • Resolution: the smallest change in the measured quantity that the instrument can detect/indicate.
  • Sensitivity: the ratio of the change in output to the change in input, S=ΔoutputΔinputS = \dfrac{\Delta\,\text{output}}{\Delta\,\text{input}} (slope of the calibration curve).

Accuracy vs Precision (target-diagram description):

CaseSpread of shotsCentred on bull's-eye?
High accuracy, high precisiontight clusteryes — on centre
Low accuracy, high precisiontight clusterno — off to one side
High accuracy, low precisionscatteredaverage near centre
Low accuracy, low precisionscatteredno

Think of a dartboard: precision is how tightly grouped the darts are; accuracy is how close that group sits to the bull's-eye. An instrument can be precise (repeatable) yet inaccurate if it carries a systematic bias.

measurement-systemserror-analysis
2long14 marks

(a) Explain the principle of operation of a Linear Variable Differential Transformer (LVDT) with a neat sketch of its construction and output characteristic curve. State two advantages and two limitations of the LVDT for displacement measurement. [8]

(b) A platinum resistance thermometer has a resistance of 100 Ω at 0 °C and a temperature coefficient of resistance α = 0.00385 /°C. It is connected in one arm of a Wheatstone bridge. Determine the resistance of the element at 150 °C and explain how a three-wire connection compensates for lead-wire resistance. [6]

(a) Linear Variable Differential Transformer (LVDT) [8]

Construction: An LVDT has one primary winding (PP) and two identical secondary windings (S1S_1, S2S_2) wound on a cylindrical former. The secondaries are connected in series opposition (phase opposition). A movable soft-iron/ferromagnetic core slides axially inside the former and is attached to the object whose displacement is measured.

        S1        P        S2
      |||||||  |||||||||  |||||||
      ====== [ core ----> ] ======
   secondary  primary    secondary  (S1 and S2 in series opposition)

Principle of operation: The primary is excited with an AC voltage. The alternating flux links both secondaries. Because they are connected in opposition, the net output is Eout=ES1ES2E_{out}=E_{S1}-E_{S2}.

  • When the core is central (null position), equal flux links both secondaries, ES1=ES2E_{S1}=E_{S2}, so Eout=0E_{out}=0.
  • When the core moves toward S1S_1, ES1>ES2E_{S1}>E_{S2}, giving a net output; moving toward S2S_2 gives output of opposite phase.

Thus the magnitude of EoutE_{out} is proportional to the displacement and the phase (relative to the primary) indicates direction.

Output characteristic: A V-shaped curve of Eout|E_{out}| versus displacement, passing through (ideally) zero at the null point, with a linear region on either side. With phase taken into account, the output is a straight line passing through the origin (positive on one side, negative on the other). A small residual voltage usually remains at null.

Advantages (any two): frictionless operation / infinite mechanical resolution; rugged, high sensitivity and good linearity over its range. Limitations (any two): sensitive to stray/external magnetic fields; needs AC excitation and demodulation; output affected by temperature and vibration.

(b) Platinum Resistance Thermometer (PT-100) [6]

Resistance variation with temperature:

Rt=R0(1+αt)R_t = R_0\,(1 + \alpha t)

Given R0=100 ΩR_0 = 100\ \Omega, α=0.00385 /C\alpha = 0.00385\ /^{\circ}\text{C}, t=150 Ct = 150\ ^{\circ}\text{C}:

R150=100(1+0.00385×150)=100(1+0.5775)=100×1.5775R_{150} = 100\,(1 + 0.00385 \times 150) = 100\,(1 + 0.5775) = 100 \times 1.5775 R150=157.75 Ω\boxed{R_{150} = 157.75\ \Omega}

Three-wire compensation: When the RTD is remote from the bridge, the two lead wires carrying current have resistance that adds directly to RtR_t, causing error that also drifts with ambient temperature. In a three-wire connection, one lead is placed in the RTD arm and a second, identical lead is placed in the adjacent bridge arm, while the third wire is the sense/galvanometer connection carrying negligible current. Because the two leads have equal resistance and are in opposite arms, their effects cancel in the bridge balance equation, so the indicated value reflects only the RTD resistance, independent of lead length and lead temperature.

transducers-and-sensorssignal-conditioning
3long12 marks

(a) Draw the block diagram of a typical digital data acquisition system (DAS) and explain the function of each block, including the multiplexer, sample-and-hold circuit, ADC and the role of the controller/computer. [7]

(b) State the Nyquist sampling theorem. A signal contains frequency components up to 4 kHz. Determine the minimum sampling frequency required and explain what aliasing is and how an anti-aliasing filter prevents it. [5]

(a) Digital Data Acquisition System (DAS) [7]

[Transducers] -> [Signal      ] -> [Multiplexer] -> [Sample &] -> [ADC] -> [Computer/   ] -> [Display/
                 [Conditioning]      (MUX)            Hold (S/H)            Controller    ]    Storage]
                                        ^________________________________________|
                                              channel-select & control
  • Transducers + signal conditioning: sensors convert physical quantities to electrical signals; conditioning amplifies, filters and level-shifts them.
  • Multiplexer (MUX): an electronic switch that sequentially connects many input channels to a single ADC, sharing the costly converter among channels (time-division multiplexing).
  • Sample-and-Hold (S/H): samples the multiplexed analog voltage at an instant and holds it constant on a capacitor during conversion, preventing the input from changing while the ADC works.
  • ADC (Analog-to-Digital Converter): converts the held analog voltage into an nn-bit digital word.
  • Controller / computer: generates timing and channel-address signals, controls MUX and S/H, reads the ADC output, and stores, processes, displays or transmits the data.

(b) Nyquist Sampling Theorem [5]

Statement: A band-limited signal containing no frequency components above fmf_m can be completely reconstructed from its samples provided the sampling frequency satisfies

fs2fm.f_s \ge 2 f_m.

For fm=4 kHzf_m = 4\ \text{kHz}:

fs(min)=2×4 kHz=8 kHz.f_{s(\min)} = 2 \times 4\ \text{kHz} = \boxed{8\ \text{kHz}}.

Aliasing: If fs<2fmf_s < 2 f_m, high-frequency components fold back and masquerade as lower frequencies in the sampled data — the original and the alias become indistinguishable, corrupting the reconstruction.

Anti-aliasing filter: a low-pass analog filter placed before the sampler. It removes (attenuates) all frequency components above fs/2f_s/2 so the input is genuinely band-limited, ensuring the Nyquist criterion is met and aliasing cannot occur.

data-acquisitiondigital-instruments
4long10 marks

(a) Draw the circuit of an instrumentation amplifier using three operational amplifiers and derive the expression for its overall voltage gain. Explain why a high common-mode rejection ratio (CMRR) is desirable in signal conditioning of bridge transducer outputs. [7]

(b) Explain the operation of a Wheatstone bridge in its balanced and unbalanced (deflection) modes, and state when each mode is preferred. [3]

(a) Three-Op-Amp Instrumentation Amplifier [7]

 V1 o--+--[A1]--+
        |       R3
        Rg              [A2 ] differential
        |       R3      stage
 V2 o--+--[A2]--+ ----> Vout
   (input buffers A1,A2 with gain resistor Rg ; output diff-amp A3)

Stage 1 (input buffers): Two non-inverting op-amps A1A_1 and A2A_2 buffer V1V_1 and V2V_2, giving very high input impedance. They are cross-coupled through the gain resistor RgR_g and two equal resistors R1R_1. The differential gain of this stage is

Vo1Vo2V1V2=1+2R1Rg.\frac{V_{o1}-V_{o2}}{V_1-V_2} = 1 + \frac{2R_1}{R_g}.

The common-mode signal passes with unity gain (no current flows through RgR_g for a common input).

Stage 2 (difference amplifier): A3A_3 with matched resistors R2,R3R_2, R_3 subtracts the two buffered signals with gain R3/R2R_3/R_2.

Overall gain:

AV=VoutV1V2=(1+2R1Rg)R3R2\boxed{A_V = \frac{V_{out}}{V_1 - V_2} = \left(1 + \frac{2R_1}{R_g}\right)\frac{R_3}{R_2}}

Gain is set by a single resistor RgR_g.

Why high CMRR is desirable: Bridge transducer outputs are small differential voltages (mV) riding on a large common-mode voltage (excitation, supply noise, pickup). A high

CMRR=20log10AdAcm dB\text{CMRR}=20\log_{10}\frac{A_d}{A_{cm}}\ \text{dB}

means the amplifier strongly rejects the common-mode part while amplifying only the wanted differential signal, preventing the large common-mode component from swamping or distorting the measurement.

(b) Balanced vs Unbalanced (Deflection) Wheatstone Bridge [3]

  • Balanced (null) mode: the variable arm is adjusted until the detector reads zero (R1R4=R2R3R_1 R_4 = R_2 R_3). The unknown is found from the known arm values. It is independent of supply voltage and gives high accuracy — preferred for precise static/calibration measurements.
  • Unbalanced (deflection) mode: the bridge is left in a fixed state and the output (off-balance) voltage is measured; it is proportional to the change in the transducer resistance. Preferred for dynamic/continuous measurement (e.g. strain-gauge transducers) where rapid, automatic readout is needed.
signal-conditioninganalog-instruments
B

Section B: Short Answer Questions

Attempt all / any as specified.

8 questions
5short7 marks

Classify the errors that occur in measurement systems into gross, systematic and random errors with one example of each. A voltage is measured five times giving readings of 50.1, 49.8, 50.0, 50.2 and 49.9 V. Compute the arithmetic mean, the standard deviation and the probable error of the readings.

Classification of Measurement Errors

  • Gross errors: human mistakes — wrong reading, incorrect recording, parallax, wrong scale. Example: misreading 25.0 V as 35.0 V.
  • Systematic errors: consistent, repeatable errors from instrument imperfection, environment or loading. Example: a meter with a zero-offset that reads 0.5 V high on every reading.
  • Random errors: unpredictable, scattered errors from unknown fluctuating causes; reduced by averaging many readings. Example: small variations due to noise/thermal effects giving slightly different readings each time.

Statistical Calculations

Readings (V): 50.1, 49.8, 50.0, 50.2, 49.9, n=5n = 5.

Arithmetic mean:

xˉ=50.1+49.8+50.0+50.2+49.95=250.05=50.0 V\bar{x} = \frac{50.1+49.8+50.0+50.2+49.9}{5} = \frac{250.0}{5} = 50.0\ \text{V}

Deviations di=xixˉd_i = x_i - \bar{x}: +0.1,0.2,0.0,+0.2,0.1+0.1,\,-0.2,\,0.0,\,+0.2,\,-0.1.

di2=0.01+0.04+0+0.04+0.01=0.10\sum d_i^2 = 0.01+0.04+0+0.04+0.01 = 0.10

Standard deviation (using n1n-1, sample):

σ=di2n1=0.104=0.025=0.158 V\sigma = \sqrt{\frac{\sum d_i^2}{n-1}} = \sqrt{\frac{0.10}{4}} = \sqrt{0.025} = 0.158\ \text{V}

(If population nn is used: σ=0.10/5=0.1414\sigma = \sqrt{0.10/5}=0.1414 V.)

Probable error of one reading:

r=0.6745σ=0.6745×0.1580.107 Vr = 0.6745\,\sigma = 0.6745 \times 0.158 \approx \boxed{0.107\ \text{V}}

Results: mean = 50.0 V, σ0.158\sigma \approx 0.158 V, probable error 0.107\approx 0.107 V.

error-analysis
6short7 marks

Define a transducer and differentiate between active and passive transducers with two examples of each. Explain, with a sketch, the working principle of a piezoelectric transducer and state one practical application.

Transducer

A transducer is a device that converts one form of energy (a physical quantity such as pressure, temperature, displacement) into another, usually into an electrical signal proportional to the measured quantity.

Active vs Passive Transducers

FeatureActive (self-generating)Passive (externally powered)
Powergenerates its own output energy from the measurandneeds an external excitation/supply
OutputEMF/charge directlychange in R, L or C
Examplesthermocouple, piezoelectric crystal, photovoltaic cell, tachogeneratorstrain gauge (R), LVDT (L), capacitive sensor (C), thermistor (R)

(any two examples of each are sufficient)

Piezoelectric Transducer

Principle: Certain crystals (quartz, barium titanate, PZT) exhibit the piezoelectric effect — when mechanical stress (force/pressure) is applied across a defined crystallographic axis, electric charges of opposite polarity appear on opposite faces, producing a voltage proportional to the applied force.

   Force F
      |
      v
  +++++++++  <- electrode (top face, +Q)
  [ crystal ]  --> Vout across faces
  ---------  <- electrode (bottom face, -Q)

The output voltage V=QC=dFCV = \dfrac{Q}{C} = \dfrac{d\,F}{C}, where dd is the piezoelectric charge constant and CC the capacitance between electrodes.

It is an active transducer and responds only to changing (dynamic) inputs.

Application (any one): measurement of dynamic pressure / vibration / acceleration (accelerometers), force/load measurement, and ultrasonic transmitters.

transducers-and-sensors
7short6 marks

Explain the working principle of a dual-slope integrating type digital voltmeter (DVM) with the help of a waveform diagram. State two advantages of the dual-slope technique over the ramp (single-slope) type DVM.

Dual-Slope Integrating DVM

Working principle: Conversion occurs in two timed phases using an integrator (op-amp + capacitor), a comparator, a control logic and a counter.

Phase 1 — fixed-time integration of the unknown: The unknown input VinV_{in} is applied to the integrator for a fixed time T1T_1 (a fixed count N1N_1 of clock pulses). The integrator output ramps with a slope proportional to VinV_{in}, reaching

Vp=VinRCT1.V_p = -\frac{V_{in}}{RC}\,T_1.

Phase 2 — fixed-slope de-integration with reference: A known reference voltage VrefV_{ref} of opposite polarity is now applied, and the integrator ramps back toward zero at a fixed slope. The counter counts clock pulses (time T2T_2) until the comparator detects zero crossing.

Since the up-ramp and down-ramp charge are equal:

VinRCT1=VrefRCT2    Vin=VrefT2T1=VrefN2N1.\frac{V_{in}}{RC}T_1 = \frac{V_{ref}}{RC}T_2 \;\Rightarrow\; V_{in} = V_{ref}\,\frac{T_2}{T_1} = V_{ref}\,\frac{N_2}{N_1}.

The count N2N_2 is therefore directly proportional to VinV_{in} and is displayed.

Waveform (described): A triangular ramp — a rising linear ramp during T1T_1 (slope Vin\propto V_{in}) up to a peak, followed by a falling linear ramp of fixed slope during T2T_2 back to zero. A larger VinV_{in} gives a higher peak and longer T2T_2.

Advantages over single-slope (ramp) type (any two):

  1. The result depends only on the ratio T2/T1T_2/T_1, so it is independent of RR, CC and exact clock frequency (they cancel), giving high accuracy and stability.
  2. Integration over a fixed time averages out (rejects) noise, especially line-frequency hum when T1T_1 is an integer multiple of the mains period.
digital-instruments
8short6 marks

Describe the construction and working of a Permanent Magnet Moving Coil (PMMC) instrument with a neat diagram. Explain how a PMMC galvanometer can be converted into (i) an ammeter using a shunt and (ii) a voltmeter using a series multiplier resistance.

PMMC Instrument — Construction and Working

Construction: A light rectangular coil of many turns of fine copper wire is wound on an aluminium former and pivoted on jewelled bearings in the air gap between the poles of a permanent magnet and a soft-iron cylindrical core. Hairsprings (also serving as current leads) provide the controlling torque and a pointer moves over a scale. Eddy currents in the aluminium former provide damping.

      N |  [coil on former]  | S
        |   pointer ----> scale
  permanent magnet + soft-iron core

Working: When current II passes through the coil placed in the radial magnetic field BB, a deflecting torque is produced:

Td=NBAI=GI(proportional to I).T_d = N B A I = G I \quad (\text{proportional to } I).

The spring's controlling torque Tc=KθT_c = K\theta balances it, so at equilibrium θI\theta \propto I — giving a uniform (linear) scale. PMMC responds only to DC (average value).

Conversion of the Galvanometer

Let full-scale deflection current be IgI_g and coil resistance RmR_m.

(i) Ammeter — shunt: Connect a low resistance RshR_{sh} in parallel with the movement to bypass the excess current. To read full scale II:

IgRm=(IIg)Rsh    Rsh=IgRmIIgI_g R_m = (I - I_g) R_{sh} \;\Rightarrow\; \boxed{R_{sh} = \frac{I_g R_m}{I - I_g}}

(ii) Voltmeter — series multiplier: Connect a high resistance RsR_s in series with the movement to drop the excess voltage. To read full scale VV:

V=Ig(Rm+Rs)    Rs=VIgRmV = I_g (R_m + R_s) \;\Rightarrow\; \boxed{R_s = \frac{V}{I_g} - R_m}
analog-instruments
9short6 marks

(a) Compare Light Emitting Diode (LED) and Liquid Crystal Display (LCD) as digital display devices in terms of power consumption, visibility and operating principle. [4]

(b) Explain how a seven-segment display is used to represent decimal digits. [2]

(a) LED vs LCD [4]

FeatureLEDLCD
Operating principlea forward-biased p-n junction emits light (electroluminescence); it is an active, light-generating deviceliquid-crystal molecules modulate/reflect ambient or back-light by changing polarization when a voltage is applied; it does not emit light
Power consumptionrelatively high (mW per segment, draws current to glow)very low (µW range, voltage-operated, almost no current)
Visibilitybright, emits its own light — clearly visible in the darkdepends on ambient light or a backlight; poor in darkness without backlight, good in bright light

(b) Seven-Segment Display [2]

A seven-segment display has seven bar-shaped segments labelled a, b, c, d, e, f, g arranged in a figure-8 (plus an optional decimal point). Each decimal digit 0–9 is formed by turning ON the appropriate subset of segments:

  • 0 -> a,b,c,d,e,f
  • 1 -> b,c
  • 7 -> a,b,c, etc.

A BCD-to-seven-segment decoder/driver (e.g. 7447 for common-anode, 7448 for common-cathode) takes the 4-bit BCD code and energizes the correct segments to display the digit.

display-devices
10short6 marks

With a neat block diagram, explain the working of a successive approximation type Analog-to-Digital Converter (ADC). For an n-bit ADC, state the expression for resolution and quantization error, and find the resolution of an 8-bit ADC with a full-scale range of 0 to 5 V.

Successive Approximation ADC (SAR)

 Vin --->|+\
         |  comparator |--> [Successive Approximation Register (SAR)] --> n-bit digital output
      +--|-/                         |  (control + bit logic)
      |                             v
      +-------------------------[ DAC ]

Working: The conversion uses a binary search controlled by the Successive Approximation Register (SAR) and an internal DAC:

  1. The SAR first sets the MSB = 1; the DAC produces the corresponding analog voltage.
  2. The comparator compares this DAC output with VinV_{in}. If VDACVinV_{DAC} \le V_{in}, the bit is kept; otherwise it is reset to 0.
  3. The process repeats from MSB to LSB, one bit per clock pulse.

After nn clock cycles the SAR holds the digital equivalent of VinV_{in}. It needs a fixed nn clock periods regardless of input — fast and widely used.

Resolution and Quantization Error

For an nn-bit ADC with full-scale range VFSV_{FS}:

Resolution=VFS2n1    (or VFS/2n for step size),Max quantization error=±12LSB.\text{Resolution} = \frac{V_{FS}}{2^{n}-1} \;\; (\text{or } V_{FS}/2^{n} \text{ for step size}), \qquad \text{Max quantization error} = \pm\tfrac{1}{2}\,\text{LSB}.

8-bit, 0–5 V:

Resolution=5 V281=5255=0.0196 V19.6 mV\text{Resolution} = \frac{5\ \text{V}}{2^{8}-1} = \frac{5}{255} = 0.0196\ \text{V} \approx \boxed{19.6\ \text{mV}}

(Using 28=2562^8 = 256 steps: 5/256=19.55/256 = 19.5 mV.) Quantization error =±9.8= \pm 9.8 mV (±12(\pm\tfrac12 LSB)).

digital-instrumentsdata-acquisition
11short6 marks

Explain the principle of a strain gauge and define its gauge factor. A strain gauge with a gauge factor of 2.0 and an unstrained resistance of 120 Ω undergoes a strain of 500 microstrain. Calculate the change in resistance of the gauge.

Strain Gauge Principle

A strain gauge is a passive resistive transducer whose electrical resistance changes when it is mechanically strained. When a metal wire/foil of length LL, area AA and resistivity ρ\rho is stretched, LL increases and AA decreases, so its resistance (R=ρL/AR = \rho L/A) increases. Bonding the gauge to a member lets it sense the surface strain.

Gauge Factor

The gauge factor (GF) relates fractional resistance change to strain ε\varepsilon:

GF=ΔR/RΔL/L=ΔR/Rε\text{GF} = \frac{\Delta R / R}{\Delta L / L} = \frac{\Delta R / R}{\varepsilon}

For common metal gauges GF 2\approx 2.

Numerical

Given GF =2.0= 2.0, R=120 ΩR = 120\ \Omega, strain ε=500 με=500×106\varepsilon = 500\ \mu\varepsilon = 500\times10^{-6}.

ΔR=GF×R×ε=2.0×120×500×106\Delta R = \text{GF}\times R \times \varepsilon = 2.0 \times 120 \times 500\times10^{-6} ΔR=2.0×120×0.0005=0.12 Ω\Delta R = 2.0 \times 120 \times 0.0005 = \boxed{0.12\ \Omega}

The gauge resistance increases by 0.12 Ω (to 120.12 Ω).

signal-conditioningtransducers-and-sensors
12short6 marks

With the help of a block diagram, explain the working of a cathode ray oscilloscope (CRO). Describe how the oscilloscope is used to measure the frequency and phase difference of two sinusoidal signals using Lissajous figures.

Cathode Ray Oscilloscope (CRO)

[Vertical input]->[Vert. amp]->+---------------------+
                               |   Cathode Ray Tube  |
[Trigger]->[Time-base/sweep]-->|  (CRT) electron gun |->[screen]
            (sawtooth) -> Horiz. amp -> X-plates       Y-plates
[Power supply for EHT & heaters]

Working: The electron gun (heater, cathode, grid, focusing & accelerating anodes) produces and focuses a narrow electron beam that strikes the phosphor screen and glows. Two pairs of deflecting plates steer the beam:

  • Vertical (Y) plates receive the amplified input signal.
  • Horizontal (X) plates receive a sawtooth (time-base) voltage that sweeps the spot left-to-right at a known rate, while the trigger circuit synchronizes the sweep so the waveform appears stationary. The result is a plot of the input voltage versus time on the screen.

Frequency and Phase Measurement using Lissajous Figures

Feed the unknown signal to the Y-plates and a known-frequency signal to the X-plates (time base off). The pattern formed is a Lissajous figure.

Frequency: Count the points where the pattern is tangent to a horizontal line and a vertical line:

fyfx=number of horizontal tangenciesnumber of vertical tangencies.\frac{f_y}{f_x} = \frac{\text{number of horizontal tangencies}}{\text{number of vertical tangencies}}.

From the known fxf_x the unknown fyf_y is found. (A 1:1 ratio with equal frequencies gives a circle/ellipse/line.)

Phase difference: For two equal-frequency sinusoids the figure is an ellipse. With

sinϕ=y1y2=x1x2,\sin\phi = \frac{y_1}{y_2} = \frac{x_1}{x_2},

where y2y_2 is the maximum vertical intercept and y1y_1 the y-intercept where the ellipse crosses the vertical axis, the phase difference ϕ\phi between the two signals is obtained. A straight diagonal line means 00^\circ or 180180^\circ; a circle means 9090^\circ.

analog-instrumentsmeasurement-systems

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